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anonymous
 3 years ago
Consider the functions f(x) = 8x + 2 and g(x) = 5x − 3. What is the value of ( )(4)? Please show all of your work for full credit.
anonymous
 3 years ago
Consider the functions f(x) = 8x + 2 and g(x) = 5x − 3. What is the value of ( )(4)? Please show all of your work for full credit.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0URRI AND ANNAS DO U NO THIS STUFF??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Consider the functions f(x) = 8x + 2 and g(x) = 5x − 3. What is the value of (F/G )(4)? Please show all of your work for full credit.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THERE THIS IS THE RIGHT VERSION OF THE QUESTION :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0WAIT THOUGH U DO 34/7 RIGHT

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0UM U NO HOW AT THE END U GOT 34/7 DO U DIVIDE 34 BY 7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i get 2 when i make it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0f(x) = 8x + 2=34 g(x) = 5x − 3=17 34/17=2

uri
 3 years ago
Best ResponseYou've already chosen the best response.2@Krabsen How are you getting 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I GOT 4.85 URI ARE U SURE U DIVIDE 34 BY 7

uri
 3 years ago
Best ResponseYou've already chosen the best response.2@Krabsen Can you show me how 17 is coming? :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0f(x) = 8x + 2=34 g(x) = 5x − 3=17 34/17=2

uri
 3 years ago
Best ResponseYou've already chosen the best response.2@Krabsen Oh my mistake! sorry i though it was 2 xd.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0KRABSEN CAN U HELP ON THIS ONE TEW Consider the functions f(x) = 3x^2 and g(x) = 2(x + 9). Find f[g(−7)]. Please show all of your work for full credit.

uri
 3 years ago
Best ResponseYou've already chosen the best response.2Ask in question box @zahabaha
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