Here's the question you clicked on:
jkev1
one number is chosen from the list 2,4,6 and 8. another is chosen from the list 6,7 and 8. Find the probability that their sum is odd
possible outcomes are 2 and 7, 4 and 7, 6 and 7 or 8 and 7. chances of picking 7 is 1/3 so required probability is 1/3