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janessia

need help!

  • one year ago
  • one year ago

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  1. janessia
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    \[x - 5\sqrt{x} +6=0\]

    • one year ago
  2. Wired
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    Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

    • one year ago
  3. timo86m
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    wired is right :)

    • one year ago
  4. janessia
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    lol well so far i got \[x-6=5\sqrt{x}\]

    • one year ago
  5. janessia
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    and idk where to go from there

    • one year ago
  6. timo86m
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    divide both sides by 5 :)

    • one year ago
  7. janessia
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    but i thought you had to square something or something like that

    • one year ago
  8. timo86m
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    isolated for sqrt(x) you not there yet div by 5 first

    • one year ago
  9. Wired
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    You can do it either way actually. I find it simpler to square both sides at that point so you don't have to deal with fractions. Those fractions would cancel out later anyway, so no need to introduce them in the first place.

    • one year ago
  10. timo86m
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    that is also true :)

    • one year ago
  11. Wired
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    \[(x-6)^{2} = (5\sqrt{x})^{2}\]

    • one year ago
  12. janessia
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    how do i do \[(5\sqrt{x})^2\]

    • one year ago
  13. timo86m
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    well (a*b) ^n is a^n*b^n right?

    • one year ago
  14. janessia
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    yes so the first is 25 and i still dont kno the second part

    • one year ago
  15. timo86m
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    25*x :) sqrt(x)^2 is x :)

    • one year ago
  16. janessia
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    oh lol im dumb lol

    • one year ago
  17. timo86m
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    no you not :)

    • one year ago
  18. janessia
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    ha ha well i think so but thanks anyway :)

    • one year ago
  19. timo86m
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    are not :P now finish the q :)

    • one year ago
  20. janessia
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    so i got\[x-36=25x\]

    • one year ago
  21. janessia
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    ?????

    • one year ago
  22. timo86m
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    that dont look right

    • one year ago
  23. janessia
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    oh wait i did it wrong sorry lol

    • one year ago
  24. janessia
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    x-36=25x???

    • one year ago
  25. timo86m
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    (x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

    • one year ago
  26. janessia
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    my head hurts

    • one year ago
  27. Wired
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    Just as an FYI, here's another way to look at squaring a square root: Note that: \[\LARGE (X^{S})^{T} = X^{ST}\] \[\LARGE \sqrt{x} = x^{1/2}\] \[\LARGE (\sqrt{x})^{2} = (x^{1/2})^{2}=x^{(1/2)(2)} = x^{1}\]

    • one year ago
  28. janessia
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    does this thing have no solution!!??? lol cuz thts wat it seems like!

    • one year ago
  29. janessia
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    ohk thnk u

    • one year ago
  30. Wired
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    \[x-6=5\sqrt{x}\] \[(x-6)^{2}=(5\sqrt{x})^{2}\] \[(x-6)(x-6)=25x\] \[x(x-6)-6(x-6)=25x\]

    • one year ago
  31. Wired
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    Do you see what to do now?

    • one year ago
  32. janessia
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    distribute?

    • one year ago
  33. Wired
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    Yep

    • one year ago
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