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janessia

  • 2 years ago

need help!

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  1. janessia
    • 2 years ago
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    \[x - 5\sqrt{x} +6=0\]

  2. Wired
    • 2 years ago
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    Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

  3. timo86m
    • 2 years ago
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    wired is right :)

  4. janessia
    • 2 years ago
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    lol well so far i got \[x-6=5\sqrt{x}\]

  5. janessia
    • 2 years ago
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    and idk where to go from there

  6. timo86m
    • 2 years ago
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    divide both sides by 5 :)

  7. janessia
    • 2 years ago
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    but i thought you had to square something or something like that

  8. timo86m
    • 2 years ago
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    isolated for sqrt(x) you not there yet div by 5 first

  9. Wired
    • 2 years ago
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    You can do it either way actually. I find it simpler to square both sides at that point so you don't have to deal with fractions. Those fractions would cancel out later anyway, so no need to introduce them in the first place.

  10. timo86m
    • 2 years ago
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    that is also true :)

  11. Wired
    • 2 years ago
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    \[(x-6)^{2} = (5\sqrt{x})^{2}\]

  12. janessia
    • 2 years ago
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    how do i do \[(5\sqrt{x})^2\]

  13. timo86m
    • 2 years ago
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    well (a*b) ^n is a^n*b^n right?

  14. janessia
    • 2 years ago
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    yes so the first is 25 and i still dont kno the second part

  15. timo86m
    • 2 years ago
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    25*x :) sqrt(x)^2 is x :)

  16. janessia
    • 2 years ago
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    oh lol im dumb lol

  17. timo86m
    • 2 years ago
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    no you not :)

  18. janessia
    • 2 years ago
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    ha ha well i think so but thanks anyway :)

  19. timo86m
    • 2 years ago
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    are not :P now finish the q :)

  20. janessia
    • 2 years ago
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    so i got\[x-36=25x\]

  21. janessia
    • 2 years ago
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    ?????

  22. timo86m
    • 2 years ago
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    that dont look right

  23. janessia
    • 2 years ago
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    oh wait i did it wrong sorry lol

  24. janessia
    • 2 years ago
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    x-36=25x???

  25. timo86m
    • 2 years ago
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    (x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

  26. janessia
    • 2 years ago
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    my head hurts

  27. Wired
    • 2 years ago
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    Just as an FYI, here's another way to look at squaring a square root: Note that: \[\LARGE (X^{S})^{T} = X^{ST}\] \[\LARGE \sqrt{x} = x^{1/2}\] \[\LARGE (\sqrt{x})^{2} = (x^{1/2})^{2}=x^{(1/2)(2)} = x^{1}\]

  28. janessia
    • 2 years ago
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    does this thing have no solution!!??? lol cuz thts wat it seems like!

  29. janessia
    • 2 years ago
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    ohk thnk u

  30. Wired
    • 2 years ago
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    \[x-6=5\sqrt{x}\] \[(x-6)^{2}=(5\sqrt{x})^{2}\] \[(x-6)(x-6)=25x\] \[x(x-6)-6(x-6)=25x\]

  31. Wired
    • 2 years ago
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    Do you see what to do now?

  32. janessia
    • 2 years ago
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    distribute?

  33. Wired
    • 2 years ago
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    Yep

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