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janessia Group Title

need help!

  • 2 years ago
  • 2 years ago

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  1. janessia Group Title
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    \[x - 5\sqrt{x} +6=0\]

    • 2 years ago
  2. Wired Group Title
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    Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

    • 2 years ago
  3. timo86m Group Title
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    wired is right :)

    • 2 years ago
  4. janessia Group Title
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    lol well so far i got \[x-6=5\sqrt{x}\]

    • 2 years ago
  5. janessia Group Title
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    and idk where to go from there

    • 2 years ago
  6. timo86m Group Title
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    divide both sides by 5 :)

    • 2 years ago
  7. janessia Group Title
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    but i thought you had to square something or something like that

    • 2 years ago
  8. timo86m Group Title
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    isolated for sqrt(x) you not there yet div by 5 first

    • 2 years ago
  9. Wired Group Title
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    You can do it either way actually. I find it simpler to square both sides at that point so you don't have to deal with fractions. Those fractions would cancel out later anyway, so no need to introduce them in the first place.

    • 2 years ago
  10. timo86m Group Title
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    that is also true :)

    • 2 years ago
  11. Wired Group Title
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    \[(x-6)^{2} = (5\sqrt{x})^{2}\]

    • 2 years ago
  12. janessia Group Title
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    how do i do \[(5\sqrt{x})^2\]

    • 2 years ago
  13. timo86m Group Title
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    well (a*b) ^n is a^n*b^n right?

    • 2 years ago
  14. janessia Group Title
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    yes so the first is 25 and i still dont kno the second part

    • 2 years ago
  15. timo86m Group Title
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    25*x :) sqrt(x)^2 is x :)

    • 2 years ago
  16. janessia Group Title
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    oh lol im dumb lol

    • 2 years ago
  17. timo86m Group Title
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    no you not :)

    • 2 years ago
  18. janessia Group Title
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    ha ha well i think so but thanks anyway :)

    • 2 years ago
  19. timo86m Group Title
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    are not :P now finish the q :)

    • 2 years ago
  20. janessia Group Title
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    so i got\[x-36=25x\]

    • 2 years ago
  21. janessia Group Title
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    ?????

    • 2 years ago
  22. timo86m Group Title
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    that dont look right

    • 2 years ago
  23. janessia Group Title
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    oh wait i did it wrong sorry lol

    • 2 years ago
  24. janessia Group Title
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    x-36=25x???

    • 2 years ago
  25. timo86m Group Title
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    (x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

    • 2 years ago
  26. janessia Group Title
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    my head hurts

    • 2 years ago
  27. Wired Group Title
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    Just as an FYI, here's another way to look at squaring a square root: Note that: \[\LARGE (X^{S})^{T} = X^{ST}\] \[\LARGE \sqrt{x} = x^{1/2}\] \[\LARGE (\sqrt{x})^{2} = (x^{1/2})^{2}=x^{(1/2)(2)} = x^{1}\]

    • 2 years ago
  28. janessia Group Title
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    does this thing have no solution!!??? lol cuz thts wat it seems like!

    • 2 years ago
  29. janessia Group Title
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    ohk thnk u

    • 2 years ago
  30. Wired Group Title
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    \[x-6=5\sqrt{x}\] \[(x-6)^{2}=(5\sqrt{x})^{2}\] \[(x-6)(x-6)=25x\] \[x(x-6)-6(x-6)=25x\]

    • 2 years ago
  31. Wired Group Title
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    Do you see what to do now?

    • 2 years ago
  32. janessia Group Title
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    distribute?

    • 2 years ago
  33. Wired Group Title
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    Yep

    • 2 years ago
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