## anonymous 4 years ago need help!

1. anonymous

$x - 5\sqrt{x} +6=0$

2. anonymous

Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

3. anonymous

wired is right :)

4. anonymous

lol well so far i got $x-6=5\sqrt{x}$

5. anonymous

and idk where to go from there

6. anonymous

divide both sides by 5 :)

7. anonymous

but i thought you had to square something or something like that

8. anonymous

isolated for sqrt(x) you not there yet div by 5 first

9. anonymous

You can do it either way actually. I find it simpler to square both sides at that point so you don't have to deal with fractions. Those fractions would cancel out later anyway, so no need to introduce them in the first place.

10. anonymous

that is also true :)

11. anonymous

$(x-6)^{2} = (5\sqrt{x})^{2}$

12. anonymous

how do i do $(5\sqrt{x})^2$

13. anonymous

well (a*b) ^n is a^n*b^n right?

14. anonymous

yes so the first is 25 and i still dont kno the second part

15. anonymous

25*x :) sqrt(x)^2 is x :)

16. anonymous

oh lol im dumb lol

17. anonymous

no you not :)

18. anonymous

ha ha well i think so but thanks anyway :)

19. anonymous

are not :P now finish the q :)

20. anonymous

so i got$x-36=25x$

21. anonymous

?????

22. anonymous

that dont look right

23. anonymous

oh wait i did it wrong sorry lol

24. anonymous

x-36=25x???

25. anonymous

(x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

26. anonymous

27. anonymous

Just as an FYI, here's another way to look at squaring a square root: Note that: $\LARGE (X^{S})^{T} = X^{ST}$ $\LARGE \sqrt{x} = x^{1/2}$ $\LARGE (\sqrt{x})^{2} = (x^{1/2})^{2}=x^{(1/2)(2)} = x^{1}$

28. anonymous

does this thing have no solution!!??? lol cuz thts wat it seems like!

29. anonymous

ohk thnk u

30. anonymous

$x-6=5\sqrt{x}$ $(x-6)^{2}=(5\sqrt{x})^{2}$ $(x-6)(x-6)=25x$ $x(x-6)-6(x-6)=25x$

31. anonymous

Do you see what to do now?

32. anonymous

distribute?

33. anonymous

Yep