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\[x - 5\sqrt{x} +6=0\]

Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

wired is right :)

lol well so far i got \[x-6=5\sqrt{x}\]

and idk where to go from there

divide both sides by 5 :)

but i thought you had to square something or something like that

isolated for sqrt(x) you not there yet div by 5 first

that is also true :)

\[(x-6)^{2} = (5\sqrt{x})^{2}\]

how do i do \[(5\sqrt{x})^2\]

well
(a*b) ^n is a^n*b^n right?

yes so the first is 25 and i still dont kno the second part

25*x :)
sqrt(x)^2 is x :)

oh lol im dumb lol

no you not :)

ha ha well i think so but thanks anyway :)

are not :P now finish the q :)

so i got\[x-36=25x\]

?????

that dont look right

oh wait i did it wrong sorry lol

x-36=25x???

(x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

my head hurts

does this thing have no solution!!??? lol cuz thts wat it seems like!

ohk thnk u

\[x-6=5\sqrt{x}\]
\[(x-6)^{2}=(5\sqrt{x})^{2}\]
\[(x-6)(x-6)=25x\]
\[x(x-6)-6(x-6)=25x\]

Do you see what to do now?

distribute?

Yep