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jkev1 Group Title

a right triangle has a leg length of 48 in and an hypotenuse of 80 in, what is the length of the other leg?

  • 2 years ago
  • 2 years ago

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  1. dpaInc Group Title
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    use the pythagorean theorem: \(\large (hypotenuse)^2=(leg_1)^2+(leg_2)^2 \)

    • 2 years ago
  2. jkev1 Group Title
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    lol I got 4096..

    • 2 years ago
  3. jkev1 Group Title
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    I think it's 70 in

    • 2 years ago
  4. dpaInc Group Title
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    or if you don't want to work with large numbers, notice that 48 = 16*3 and 80=16*5. they both have a common factor of 16 so just work with a leg of 3 and hypotenuse of 5... just be sure to multiply your answer by 16 at the end..

    • 2 years ago
  5. jkev1 Group Title
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    is it 56 in?

    • 2 years ago
  6. jkev1 Group Title
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    @dpaInc

    • 2 years ago
  7. dpaInc Group Title
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    how did you get 56?

    • 2 years ago
  8. dpaInc Group Title
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    while we're at it, how did you get 70?

    • 2 years ago
  9. dpaInc Group Title
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    even if one of them is correct i need to see how you got it so i can say, "yes, it's correct"

    • 2 years ago
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