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jkev1

  • 2 years ago

a right triangle has a leg length of 48 in and an hypotenuse of 80 in, what is the length of the other leg?

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  1. dpaInc
    • 2 years ago
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    use the pythagorean theorem: \(\large (hypotenuse)^2=(leg_1)^2+(leg_2)^2 \)

  2. jkev1
    • 2 years ago
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    lol I got 4096..

  3. jkev1
    • 2 years ago
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    I think it's 70 in

  4. dpaInc
    • 2 years ago
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    or if you don't want to work with large numbers, notice that 48 = 16*3 and 80=16*5. they both have a common factor of 16 so just work with a leg of 3 and hypotenuse of 5... just be sure to multiply your answer by 16 at the end..

  5. jkev1
    • 2 years ago
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    is it 56 in?

  6. jkev1
    • 2 years ago
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    @dpaInc

  7. dpaInc
    • 2 years ago
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    how did you get 56?

  8. dpaInc
    • 2 years ago
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    while we're at it, how did you get 70?

  9. dpaInc
    • 2 years ago
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    even if one of them is correct i need to see how you got it so i can say, "yes, it's correct"

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