jkev1
a right triangle has a leg length of 48 in and an hypotenuse of 80 in, what is the length of the other leg?
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dpaInc
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use the pythagorean theorem: \(\large (hypotenuse)^2=(leg_1)^2+(leg_2)^2 \)
jkev1
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lol I got 4096..
jkev1
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I think it's 70 in
dpaInc
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or if you don't want to work with large numbers, notice that 48 = 16*3 and 80=16*5.
they both have a common factor of 16 so just work with a leg of 3 and hypotenuse of 5... just be sure to multiply your answer by 16 at the end..
jkev1
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is it 56 in?
jkev1
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@dpaInc
dpaInc
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how did you get 56?
dpaInc
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while we're at it, how did you get 70?
dpaInc
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even if one of them is correct i need to see how you got it so i can say, "yes, it's correct"