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anonymous
 4 years ago
solve. then round answer to the nearest hundredth. 6^x3=52
anonymous
 4 years ago
solve. then round answer to the nearest hundredth. 6^x3=52

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1342135467157:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[6^{x3} = 52\]You will need to use logarithms to solve this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Specifically, you will need to use the property of logarithms such that will allow you to work with the exponent: So, if you have \[x^y\], if you take the log of this you obtain: \[log_a(x^y) = y * log_a(x)\]The exponent now becomes a factor in the product

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For your equation, you will want to take the logarithm of both sides, then you can solve for x. You can use any base for the logarithm: \[log_a\] I'm sure you're familiar with the concept of logarithms, but here is nice way to remember what it does: you can say that when you have the expression: \[log_ab = x\]You are looking for the number you raise 'a' to in order to obtain 'b' is 'x'. \[a^x = b\] \[log_28=3\]The number you raise 2 to in order to obtain the value 8, is 3. \[2^3 = 8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Does this seem familiar or helpful?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK, cool, I see that you had a similar question  http://openstudy.com/users/coolaidd#/updates/4fff44afe4b09082c0707aad

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you think you can solve this problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0log_5 x=3 x = 5^3 = 125

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.06^(x  3) = 52 (x  3) ln 6 = ln 52 x  3 = ln 52/ln 6 x = 3 + ln 52/ln 6 ≈ 5.20523

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, good luck with the rest of your studies! Maybe you can help with some questions even ;)
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