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coolaidd

  • 2 years ago

solve. then round answer to the nearest hundredth. 10^x+4=1000

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  1. coolaidd
    • 2 years ago
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    @dpflan

  2. dpflan
    • 2 years ago
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    Is it\[10^{x+4} = 1000\] In anyway case, it's just like the last one, you can solve this one in a minute ;)

  3. coolaidd
    • 2 years ago
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    yes..

  4. coolaidd
    • 2 years ago
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    10^x+4=1000 10^x = 996 x = log 996 2.9982

  5. dpflan
    • 2 years ago
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    wait, if it's \[10^{x+4}\] then you need to re-solve

  6. dpflan
    • 2 years ago
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    Otherwise, you got it

  7. coolaidd
    • 2 years ago
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    so if it is 10^x+4 its wrong?

  8. dpflan
    • 2 years ago
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    No, you solved it correctly if the +4 is not in the exponent

  9. dpaInc
    • 2 years ago
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    be careful of what you're solving... which of these is the correct expression on the left: \[\large 10^{x+4} \] or \[\large 10^{x}+4 \]

  10. coolaidd
    • 2 years ago
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    the first one

  11. dpaInc
    • 2 years ago
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    then like @dpflan , said, you need to resolve... your original solution is for the second expression

  12. coolaidd
    • 2 years ago
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    10^(x + 4) = 1000 x + 4 = 3 x = -1

  13. dpflan
    • 2 years ago
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    yeah, nice!

  14. coolaidd
    • 2 years ago
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    how would i round that to the nearest hundredth though?

  15. coolaidd
    • 2 years ago
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    ?

  16. dpflan
    • 2 years ago
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    Well, it currently have no fractional value, nothing passed the decimal point, so you can rewrite that \[-1=-1.00000....\]

  17. coolaidd
    • 2 years ago
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    thanks :)

  18. dpflan
    • 2 years ago
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    No problem, thanks for the medal!

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