coolaidd
solve. then round answer to the nearest hundredth. log_5x=3
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coolaidd
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@dpflan ?
dpflan
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\[log_5x=3\]Is that the equation?
coolaidd
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yess
dpflan
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\[log_ab=x\] OK, this means, the number you raise a to in order to obtain x is b. so \[a^x = b\]
coolaidd
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ok..
coolaidd
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would it be x = 5^3 = 125?
dpflan
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\[log_5x=3\] Is \[5^3 = x\]...
Yeah you got it
coolaidd
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what is 125 to the nearest..?
dpflan
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\[125 = 125.00000...\]
dpflan
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just like the last one ;)
coolaidd
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what would 35 be rounded to the hundredth? 35.000?
coolaidd
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?
dpflan
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Actually, no, you need one less 0. Using the decimal system, the values to the right of the decimal are fractional amounts with respect the base for the system, which is 10 here.
So the first place would be \[10^{-1}\] which is 1/10, the second place is \[10^{-2}\] which is \[\frac{1}{10^2}=\frac{1}{100}\] , this that is the "hundredths" place
dpflan
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so just two points to the right would be to the nearest hundrdeth
coolaidd
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cool..it didnt have anything to do with the previous question..
coolaidd
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i just wanted to know what 35 rounded to the nearest hundredth would be
dpflan
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It's actually kind of cool, you use any number as the base.
So if you have 123.456, then you have \[1*10^3 + 2*10^1 + 2*10^0 + 4*10^{-1} + 5*10^{-2} + 6*10^{-3}\]
dpflan
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At least in the decimal system
coolaidd
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is that for 35?
dpflan
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No, 35 is 35.00