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dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1\[log_5x=3\]Is that the equation?

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1\[log_ab=x\] OK, this means, the number you raise a to in order to obtain x is b. so \[a^x = b\]

coolaidd
 2 years ago
Best ResponseYou've already chosen the best response.0would it be x = 5^3 = 125?

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1\[log_5x=3\] Is \[5^3 = x\]... Yeah you got it

coolaidd
 2 years ago
Best ResponseYou've already chosen the best response.0what is 125 to the nearest..?

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1just like the last one ;)

coolaidd
 2 years ago
Best ResponseYou've already chosen the best response.0what would 35 be rounded to the hundredth? 35.000?

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1Actually, no, you need one less 0. Using the decimal system, the values to the right of the decimal are fractional amounts with respect the base for the system, which is 10 here. So the first place would be \[10^{1}\] which is 1/10, the second place is \[10^{2}\] which is \[\frac{1}{10^2}=\frac{1}{100}\] , this that is the "hundredths" place

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1so just two points to the right would be to the nearest hundrdeth

coolaidd
 2 years ago
Best ResponseYou've already chosen the best response.0cool..it didnt have anything to do with the previous question..

coolaidd
 2 years ago
Best ResponseYou've already chosen the best response.0i just wanted to know what 35 rounded to the nearest hundredth would be

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1It's actually kind of cool, you use any number as the base. So if you have 123.456, then you have \[1*10^3 + 2*10^1 + 2*10^0 + 4*10^{1} + 5*10^{2} + 6*10^{3}\]

dpflan
 2 years ago
Best ResponseYou've already chosen the best response.1At least in the decimal system
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