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dpflanBest ResponseYou've already chosen the best response.1
\[log_5x=3\]Is that the equation?
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
\[log_ab=x\] OK, this means, the number you raise a to in order to obtain x is b. so \[a^x = b\]
 one year ago

coolaiddBest ResponseYou've already chosen the best response.0
would it be x = 5^3 = 125?
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
\[log_5x=3\] Is \[5^3 = x\]... Yeah you got it
 one year ago

coolaiddBest ResponseYou've already chosen the best response.0
what is 125 to the nearest..?
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
just like the last one ;)
 one year ago

coolaiddBest ResponseYou've already chosen the best response.0
what would 35 be rounded to the hundredth? 35.000?
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
Actually, no, you need one less 0. Using the decimal system, the values to the right of the decimal are fractional amounts with respect the base for the system, which is 10 here. So the first place would be \[10^{1}\] which is 1/10, the second place is \[10^{2}\] which is \[\frac{1}{10^2}=\frac{1}{100}\] , this that is the "hundredths" place
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
so just two points to the right would be to the nearest hundrdeth
 one year ago

coolaiddBest ResponseYou've already chosen the best response.0
cool..it didnt have anything to do with the previous question..
 one year ago

coolaiddBest ResponseYou've already chosen the best response.0
i just wanted to know what 35 rounded to the nearest hundredth would be
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
It's actually kind of cool, you use any number as the base. So if you have 123.456, then you have \[1*10^3 + 2*10^1 + 2*10^0 + 4*10^{1} + 5*10^{2} + 6*10^{3}\]
 one year ago

dpflanBest ResponseYou've already chosen the best response.1
At least in the decimal system
 one year ago
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