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virtus
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1342145485490:dw In the figure above, if the area of triangle AQD is 20 square cm and AQ: QB = 2:3 find the area of the parallelogram ABCD

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.2Okay, so that triangle and the parallelogram have the same height, which is what will let us solve this. Let me define the variable h=height, both of the triangle and parallelogram Area of the triangle = (1/2)h*(AQ) = 20 Area of the parallelogram = base*height = (AQ + QB)*h QB = (3/2)*AQ

SmoothMath
 2 years ago
Best ResponseYou've already chosen the best response.2(AQ + QB) = (AQ + (3/2)AQ) = (5/2)AQ So the area of the parallelogram = (5/2)AQ*h And we know that (1/2)AQ*h = 20 from the triangle.

virtus
 2 years ago
Best ResponseYou've already chosen the best response.0thankyou @JohnHanShanghai
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