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|dw:1342145485490:dw| In the figure above, if the area of triangle AQD is 20 square cm and AQ: QB = 2:3 find the area of the parallelogram ABCD
Okay, so that triangle and the parallelogram have the same height, which is what will let us solve this. Let me define the variable h=height, both of the triangle and parallelogram Area of the triangle = (1/2)h*(AQ) = 20 Area of the parallelogram = base*height = (AQ + QB)*h QB = (3/2)*AQ
(AQ + QB) = (AQ + (3/2)AQ) = (5/2)AQ So the area of the parallelogram = (5/2)AQ*h And we know that (1/2)AQ*h = 20 from the triangle.
thankyou @JohnHanShanghai