A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
question posted below
anonymous
 4 years ago
question posted below

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1342145485490:dw In the figure above, if the area of triangle AQD is 20 square cm and AQ: QB = 2:3 find the area of the parallelogram ABCD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, so that triangle and the parallelogram have the same height, which is what will let us solve this. Let me define the variable h=height, both of the triangle and parallelogram Area of the triangle = (1/2)h*(AQ) = 20 Area of the parallelogram = base*height = (AQ + QB)*h QB = (3/2)*AQ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(AQ + QB) = (AQ + (3/2)AQ) = (5/2)AQ So the area of the parallelogram = (5/2)AQ*h And we know that (1/2)AQ*h = 20 from the triangle.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thankyou @JohnHanShanghai
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.