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Rickolocity Group Title

find the required number TU=3 RS=15 TW=4 TR=9 UW=

  • 2 years ago
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  1. cherylim23 Group Title
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    UW = UT + TW = -3 + 4 = 1?

    • 2 years ago
  2. Rickolocity Group Title
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    here is a photo to help explain better

    • 2 years ago
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  3. cherylim23 Group Title
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    I thought it was vectors, well... 3/9 = UW/15 Solve that and UW = 5

    • 2 years ago
  4. Wired Group Title
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    \[\frac{TU}{TR}=\frac{UW}{RS}\] \[\frac{3}{9}=\frac{UW}{15}\] Cross multiply: 45=9(UW)

    • 2 years ago
  5. Rickolocity Group Title
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    what about This one. What is WS

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