Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Rainbow_Dash

log(2) (12b-21) - log(2) (b^2 - 3) = 2

  • one year ago
  • one year ago

  • This Question is Closed
  1. ProgramGuru
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\log_{2}((12b-1)/ (b ^{2}-3))=2\log_{2}2 \] \[(12b-3)/(b ^{2}-3)=4\] Now solve the quadratic to get value of b!

    • one year ago
  2. ProgramGuru
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry it will be 12b-21

    • one year ago
  3. Wired
    Best Response
    You've already chosen the best response.
    Medals 2

    Log Quotient Rule: \[\Large \log_{b}({A/C}) = \log_{b}A − \log_{b}C\] Applying that gets you: \[\Large \log_{2}{(12b-21)}-\log_{2}{(b^{2}-3)}=2\] \[\Large \log_{2}{\frac{(12b-21)}{(b^{2}-3)}}=2\] \[\Large x=c^{y}\] \[\Large log_{c}{x}=y\] \[\Large X = \frac{(12b-21)}{(b^{2}-3)}\] \[\Large Y = 2\] \[\Large C = 2\] \[\Large 2^{2} = \frac{(12b-21)}{(b^{2}-3)}\] \[\Large 4b^{2}-12= 12b-21\] \[\Large 4b^{2}-12= 12b-21\] \[\Large 4b^{2}-12b+9=0\]

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.