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## Rainbow_Dash 2 years ago log(2) (12b-21) - log(2) (b^2 - 3) = 2

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1. ProgramGuru

$\log_{2}((12b-1)/ (b ^{2}-3))=2\log_{2}2$ $(12b-3)/(b ^{2}-3)=4$ Now solve the quadratic to get value of b!

2. ProgramGuru

sorry it will be 12b-21

3. Wired

Log Quotient Rule: $\Large \log_{b}({A/C}) = \log_{b}A − \log_{b}C$ Applying that gets you: $\Large \log_{2}{(12b-21)}-\log_{2}{(b^{2}-3)}=2$ $\Large \log_{2}{\frac{(12b-21)}{(b^{2}-3)}}=2$ $\Large x=c^{y}$ $\Large log_{c}{x}=y$ $\Large X = \frac{(12b-21)}{(b^{2}-3)}$ $\Large Y = 2$ $\Large C = 2$ $\Large 2^{2} = \frac{(12b-21)}{(b^{2}-3)}$ $\Large 4b^{2}-12= 12b-21$ $\Large 4b^{2}-12= 12b-21$ $\Large 4b^{2}-12b+9=0$

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