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## Rainbow_Dash Group Title log(7) 1/343 2 years ago 2 years ago

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1. jrzyby1

-3

2. shandelman

@jrzyby1 It is against the code of conduct of the site to just give answers ESPECIALLY with zero explanation.

3. Wired

$\Large b^{y}=x$ $\Large \log_{b}{x}=y$ $\Large \log_{7}{\frac{1}{343}}=y$ $\Large 7^{y}=\frac{1}{343}=343^{-1}$ $\Large 7^{y}=343^{-1}$ Solve.

4. jiteshmeghwal9

$\log_{7}{1 \over 343}=x$can change it into exponential form as$7^x=\frac{1}{343}$& u can write it as$7^x=343^{-1}$$7^x=(7^3)^{-1}$now u know that if the bases are equal then powers are also equal so u can write the equation as$x=3+(-1)$$x=2$

5. ParthKohli

Oopsie. Mistake here. ^

6. ParthKohli

$$\color{Black}{\Rightarrow 7^{x} = 7^{-3}}$$ $$\color{Black}{\Rightarrow x = -3}$$

7. ParthKohli

I think you confused $$(7^3)^{-1}$$ with $$7^3 \times 7^{-1}$$

8. jiteshmeghwal9

i m sorry @ParthKohli . I was really confused