Compassionate
Y = -2x + 3, how would I graph the -2x part?
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ineedhelponmyhw
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every X-axis number, go down 2 (y-axis numbers)
Mimi_x3
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\[y=-2x+3\]
To skectch; find the \(x\) intercept and \(y\) intercept.
\(y\)-interecept: \(x\) = \(0\)
\(x\)-intercept: \(y\)\=\(0\)
Compassionate
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I'm asking how I would work the equation out and do the whole (-1, 1) thing.
ineedhelponmyhw
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Y=Mx+B
ineedhelponmyhw
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the "B" is the number on the y-axis
ineedhelponmyhw
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ineedhelponmyhw
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are you still confused?
Compassionate
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Yes.
ineedhelponmyhw
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sorry i didnt see it was -2, i thought it was positive 2.................after you find the "b" you go down 2 (to the right)
ineedhelponmyhw
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ineedhelponmyhw
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(0,3).....(1,1).....(2,-1)
Compassionate
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So I find B by graphing 3, and then go down -2?
Compassionate
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Why did it go over 1?
ineedhelponmyhw
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that how you graph it.....
ineedhelponmyhw
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after you find the "dots" on the graph, you can make a line
ineedhelponmyhw
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ineedhelponmyhw
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ineedhelponmyhw
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heres a site (just for in case. lol)
Compassionate
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Why did my negative 2 become positive, and where did (2, -1) come from -_-
ineedhelponmyhw
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Compassionate
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So I basically put 1 over the number with the x next to it. +3 = 3, and 2x = 1/2x which means down 2, and over one, which will give me the correct answer.
ineedhelponmyhw
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its becoming negative not positive
Compassionate
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Kk
ineedhelponmyhw
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"So I basically put 1 over the number with the x next to it.".....yes, the x is the x-axis
Compassionate
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okay.
ineedhelponmyhw
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the "+3" lies on the y-axis
ineedhelponmyhw
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which is why i started off with (0,3).......it doesnt lie on the x-axis [x,y] < the 3 replaces the y.
ineedhelponmyhw
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ineedhelponmyhw
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ineedhelponmyhw
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ineedhelponmyhw
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ineedhelponmyhw
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do you get it now????
ineedhelponmyhw
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it will help you hopefully