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calculate the length of AB, giving your answer correct to one decimal place

Are you allowed to use the law of cosines?

use the law of cosines....
\(\large (AB)^2=(AC)^2+(BC)^2-2(AC)(BC)cosC \)

...I didn't get a whole answer, but I also didn't get 7.2. Hmm...

Oh, wait. Hold on.

No, I did get 7.2, never mind.
c^2 = 6^2 + 8^2 - 2(6)(8)cos(60)

oh i must have made a mistake then! THANKS

I get 13.8 for some reason

put the calculator in degrees measure.. .