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what is the expected value of x^2 in mathematical form?

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in a simplified form
what do you mean?
\(x \times x\) I think that's what you mean.

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Other answers:

mathematical form?
Hmm. Similarly: \( \color{Black}{\Rightarrow x^3 = x \times x\times x}\) \( \color{Black}{\Rightarrow x^4 = x \times x \times x \times x}\)
'Mathematical form' is still ambiguous.
some stats people know may know
\[\langle x^2\rangle =\sum\limits_{j=0}^\infty x^2 P(j)\]
\[\int 2xdx\]
this reminds me of a very fundamental/basic question in calculus..please see my next question..i'll post link..
\[\frac{d}{dx} (\frac{x^3}{3})\]
what are you doing at @lgbasallote ,
\[x^2 = r^2 - y^2\]
trying to get all that's x^2 and see if anythign suits him
im pretty sure i have provided the answer to the question
we all think that...
i need E(x^2)=?
the expectiation value of \(x\) \[\langle x\rangle =E(x)\]
@UnkleRhaukus yes but x^2
i got the ans... thanks all
\[\sigma_x=\langle x^2\rangle-\langle x\rangle ^2\]
ya ur right
The expectation value , or expect value of a function is \[\langle f(x)\rangle =\sum\limits_{x=0}^\infty f(x)P(x)\] where \(P(x)\) is the probability of x
yes for a discrete random variable
im not sure why i put j instead of x,
oh, you want a continuous function?
no i know
thank you
\[\langle f(x)\rangle=\int\limits_{-\infty}^\infty f(x)\rho(x)\text dx\]
where \(\rho(x)\) is the probability density
so \[\langle x^2\rangle=\int\limits_{-\infty}^\infty x^2\rho(x)\text dx\]
@UnkleRhaukus small question the E(constant) is a constant right
if the distribution of the variable \(x\) is constant , yes

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