GEOMETRY QUES:
its a good ques,please try it

- anonymous

GEOMETRY QUES:
its a good ques,please try it

- chestercat

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

|dw:1342192872407:dw|
value of x ?

- anonymous

I think \[x = 105\]
im not sure

- anonymous

nop..not the ans..
you have any method or guessing?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

@ParthKohli @experimentX @eliassaab @jhonyy9 @shubhamsrg @sam

- anonymous

Can you get a picture up???

- anonymous

i had this drawing..what do you mean by picture up ?

- anonymous

@maheshmeghwal9 @mukushla @Romero @ganeshie8

- maheshmeghwal9

|dw:1342192775085:dw|

- maheshmeghwal9

|dw:1342192880199:dw|

- maheshmeghwal9

|dw:1342192995755:dw|

- maheshmeghwal9

|dw:1342193136068:dw|

- anonymous

altough you're trying to make some progress but leme tell you,,its in vain till now! ;)

- maheshmeghwal9

Take each triangle in consideration
i think u would get the answer

- anonymous

try it..you wont by this method..

- maheshmeghwal9

see the last figure properly:)
there is ur answer in it
u would get 100%

- anonymous

an eqn in x and y,,what else do you get ?

- maheshmeghwal9

no equation in y
only equation in x
get the y in the form of x from the last figure

- maheshmeghwal9

okay lemme try first:)

- anonymous

show me..100 rs and a medal if you are able to! ;)

- anonymous

are you sure that question is right ? :P

- anonymous

Actually in this question I am able to form only one equation , which is x-y = 60 ! So not sure, still Iam trying ! :-)

- maheshmeghwal9

i also think that in question
something is missing
otherwise
somebody had done it upto now
by the way all members are intelligent.

- anonymous

@Aryang Can you put an actual picture because I don't understand the drawing. I want to help but I don't understand the drawing. Sorry

- anonymous

x=130

- anonymous

is it ryt...

- shubhamsrg

Lets do some construction :
A circumcirle around ACB is constructed
Now, angle O is 110 degrees, if it were to lie on the circle, it should have been 55 degrees so as to fulfill cyclic quad criteria. Since it is greater than that, it will lie inside the circle.
|dw:1342256886064:dw|
let BO extend to D and lets join DA and DC.
DACB is now a cyclic quad
now, = = 25
also, ==30
now, = 130 , which gives us as 25
=>DO = OC
similarly, =120 , which gives us as 30
=>DO = OA
=>DO=OA=OC
thus = = 35
=>x= 95 degrees <--ans..
by the way, if you inspect clearly , O is the center of the circle.
CASE CLOSED! ;)

- shubhamsrg

PARDON ME FOR MY DRAWING ! :p

- anonymous

correct <--yet again @shubhamsrg
@maheshmeghwal9 you even got 3 medals !! lol.. :D

- anonymous

is the ans posted by shubhamsrg correct ?

- anonymous

The method of circumscribing seems fine to me , but can we really assume O to be the centre ?

- phi

This problem is unconstrained, and there are many answers for x
For example.
|dw:1342280867011:dw|
all the interior angles of the triangles sum to 180, and the interior angles of the quadrilateral sum to 360.

- anonymous

can you please explain step by step , the drawing is a bit messy and confusing !

- shubhamsrg

@phi ,, can you explain ? o.O

- shubhamsrg

@anjali_pant i didnt assume that to be the center..i solved it without considering that fact.
i just said that if you inspect further, you can prove O is the center.

- anonymous

@anjali_pant yes he's correct as far as i am concerned,,
@phi yes..i think you're going wrong somewhere..

- anonymous

ok thanks people !!! :-)

- phi

Are you saying my posted triangle violates the given conditions or is impossible to construct? If so, prove it (it will take you a very long time)
the problem with shub's idea is that he chose a point D on the circumcircle such that DOB is a straight line. He introduced a new constraint not in the original problem. If he put D somewhere else on the circle (nothing in the problem prevents this) he would get a different answer for x.

- shubhamsrg

@phi
am totally confused what you are trying to point out..
i first circumscribed it then got my by extending that line..
maybe construction by hand using protractor and other stuff might help..

- phi

You can extend the line so that line DOB is a straight line with D on the circumcircle.
However, you could put D elsewhere on the circle so that DOB is not a straight line. If you do, you will get a different answer for x. In other words, because you picked a specific cyclic quadrilateral, you get a specific value for x. But you can pick a different cyclic quadrilateral (agreed?). If you do, you get a different x

- shubhamsrg

ok i'll be back to it..

Looking for something else?

Not the answer you are looking for? Search for more explanations.