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Aryang Group TitleBest ResponseYou've already chosen the best response.3
dw:1342192872407:dw value of x ?
 2 years ago

sOcCeR_fReAk7007 Group TitleBest ResponseYou've already chosen the best response.0
I think \[x = 105\] im not sure
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
nop..not the ans.. you have any method or guessing?
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
@ParthKohli @experimentX @eliassaab @jhonyy9 @shubhamsrg @sam
 2 years ago

sOcCeR_fReAk7007 Group TitleBest ResponseYou've already chosen the best response.0
Can you get a picture up???
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
i had this drawing..what do you mean by picture up ?
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
@maheshmeghwal9 @mukushla @Romero @ganeshie8
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
dw:1342192775085:dw
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
dw:1342192880199:dw
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
dw:1342192995755:dw
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
dw:1342193136068:dw
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
altough you're trying to make some progress but leme tell you,,its in vain till now! ;)
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
Take each triangle in consideration i think u would get the answer
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
try it..you wont by this method..
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
see the last figure properly:) there is ur answer in it u would get 100%
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
an eqn in x and y,,what else do you get ?
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
no equation in y only equation in x get the y in the form of x from the last figure
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
okay lemme try first:)
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
show me..100 rs and a medal if you are able to! ;)
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
are you sure that question is right ? :P
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
Actually in this question I am able to form only one equation , which is xy = 60 ! So not sure, still Iam trying ! :)
 2 years ago

maheshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.3
i also think that in question something is missing otherwise somebody had done it upto now by the way all members are intelligent.
 2 years ago

sOcCeR_fReAk7007 Group TitleBest ResponseYou've already chosen the best response.0
@Aryang Can you put an actual picture because I don't understand the drawing. I want to help but I don't understand the drawing. Sorry
 2 years ago

prasannalakshmi Group TitleBest ResponseYou've already chosen the best response.0
x=130
 2 years ago

prasannalakshmi Group TitleBest ResponseYou've already chosen the best response.0
is it ryt...
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
Lets do some construction : A circumcirle around ACB is constructed Now, angle O is 110 degrees, if it were to lie on the circle, it should have been 55 degrees so as to fulfill cyclic quad criteria. Since it is greater than that, it will lie inside the circle. dw:1342256886064:dw let BO extend to D and lets join DA and DC. DACB is now a cyclic quad now, <CDB>=<CAB> = 25 also, <BDA>=<BCA>=30 now, <DOC> = 130 , which gives us <DCO> as 25 =>DO = OC similarly, <DOA>=120 , which gives us <DAO> as 30 =>DO = OA =>DO=OA=OC thus <OCA> = <OAC> = 35 =>x= 95 degrees <ans.. by the way, if you inspect clearly , O is the center of the circle. CASE CLOSED! ;)
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
PARDON ME FOR MY DRAWING ! :p
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
correct <yet again @shubhamsrg @maheshmeghwal9 you even got 3 medals !! lol.. :D
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
is the ans posted by shubhamsrg correct ?
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
The method of circumscribing seems fine to me , but can we really assume O to be the centre ?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
This problem is unconstrained, and there are many answers for x For example. dw:1342280867011:dw all the interior angles of the triangles sum to 180, and the interior angles of the quadrilateral sum to 360.
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
can you please explain step by step , the drawing is a bit messy and confusing !
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
@phi ,, can you explain ? o.O
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
@anjali_pant i didnt assume that to be the center..i solved it without considering that fact. i just said that if you inspect further, you can prove O is the center.
 2 years ago

Aryang Group TitleBest ResponseYou've already chosen the best response.3
@anjali_pant yes he's correct as far as i am concerned,, @phi yes..i think you're going wrong somewhere..
 2 years ago

anjali_pant Group TitleBest ResponseYou've already chosen the best response.0
ok thanks people !!! :)
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
Are you saying my posted triangle violates the given conditions or is impossible to construct? If so, prove it (it will take you a very long time) the problem with shub's idea is that he chose a point D on the circumcircle such that DOB is a straight line. He introduced a new constraint not in the original problem. If he put D somewhere else on the circle (nothing in the problem prevents this) he would get a different answer for x.
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
@phi am totally confused what you are trying to point out.. i first circumscribed it then got my by extending that line.. maybe construction by hand using protractor and other stuff might help..
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
You can extend the line so that line DOB is a straight line with D on the circumcircle. However, you could put D elsewhere on the circle so that DOB is not a straight line. If you do, you will get a different answer for x. In other words, because you picked a specific cyclic quadrilateral, you get a specific value for x. But you can pick a different cyclic quadrilateral (agreed?). If you do, you get a different x
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.3
ok i'll be back to it..
 2 years ago
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