anonymous
  • anonymous
A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t2+150t gives the height in feet of Zinger 1 at t seconds after launch. The polynomial: -16t2 + 165t gives the height of Zinger 2 at t seconds after launch. If the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is Zinger 2 than Zinger 1 when they explode? Explain your answer to me so I could understand.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
A. 414 ft B. 990 ft C. 90 ft D. 324 ft
hba
  • hba
#4. Plug t = 6 into the two formulas. Zinger 1: -16 * t^2 + 150 * t = -16 * 6^2 + 150 * 6 = Zinger 2: -16 * t^2 + 165 * t = -16 * 6^2 + 165 * 6 =
anonymous
  • anonymous
okay 414 ?

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hba
  • hba
did u calculate it
anonymous
  • anonymous
yes I got that tho ... I had used that formula but i dnt know if my answer is right.
hba
  • hba
wait let me calculate
anonymous
  • anonymous
never mind check this one distance that Z1 travels = -16(6)^2+150(6) distance that Z2 travels = -16(6)^2 + 165(6) distance between them = -16(6)^2 + 165(6) - (-16(6)^2+150(6)) = 90
anonymous
  • anonymous
I'm i right
hba
  • hba
414 is correct
anonymous
  • anonymous
are you sure I did it again... distance that Z1 travels = -16(6)^2+150(6) distance that Z2 travels = -16(6)^2 + 165(6) distance between them = -16(6)^2 + 165(6) - (-16(6)^2+150(6)) = 90
hba
  • hba
Substituting the value t = 6 in the first equation gives: (-16 * 36) + (165 * 6) = -576 + 990 = 414
hba
  • hba
this is what the first polynomial gives
anonymous
  • anonymous
ohhh okay so then my work was wrong...okay then I get it ...
anonymous
  • anonymous
thank you again..
hba
  • hba
Ur welcome

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