Here's the question you clicked on:
agentx5
Converting Cartesian coordinates into polar coordinates. (x,y) = (3,-5) (r,\(\theta\)) = (\(\sqrt{34}\),???) \(r=\sqrt{(3)^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}\) \(\theta = tan^{-1}(\frac{(-5)}{(3)})=???\) My answer needs to be in radians an I'm not seeing how the unit circle is going to be of much help here. It's not a nice angle like \(\frac{\pi}{2}\), \(\frac{\pi}{3}\), \(\frac{\pi}{4}\), \(\frac{\pi}{6}\), or \(\pi\)
I don't think it's going to let me take it as a decimal though, especially since is a irrational, non-repeating decimal: http://www.wolframalpha.com/input/?i=tan^%28-1%29+%28-5%2F3%29
it will be most probably \[-\pi/3\]
I was hoping Wolf would help me convert, but alas it appears not... |dw:1342210050046:dw|
Actually that's fairly close annas The actual value is -1.030376827... (radians) -\(\frac{\pi}{3}\) is -1.047197551... (radians)
Let me see if it takes it after I do the rest of the problem, if it does, you getz a cookie :-3
\[\frac{-\pi}{3} \rightarrow \frac{5\pi}{3}\] Yes? And... (\(\large-\sqrt{34},\frac{2\pi }{3}\)) is the valid r<0 value, yes?
I don't know what they were expecting here. It's not quite a 3-4-5 triangle here, the 5 is on the opposite side, not the hypoteneuse
Proof that I can't make this stuff up, and that it's the only one for this part giving me issues:
But it's not correct yet m'dear! ^_^
yap thats why i said "eat cookies now !!!!"
*idea* I'm going to try 180/\(\pi\) to convert and see if I can recognize it