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- anonymous

Converting Cartesian coordinates into polar coordinates.
(x,y) = (3,-5)
(r,\(\theta\)) = (\(\sqrt{34}\),???)
\(r=\sqrt{(3)^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}\)
\(\theta = tan^{-1}(\frac{(-5)}{(3)})=???\)
My answer needs to be in radians an I'm not seeing how the unit circle is going to be of much help here. It's not a nice angle like \(\frac{\pi}{2}\), \(\frac{\pi}{3}\), \(\frac{\pi}{4}\), \(\frac{\pi}{6}\), or \(\pi\)

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- anonymous

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- anonymous

-59.036

- anonymous

I don't think it's going to let me take it as a decimal though, especially since is a irrational, non-repeating decimal:
http://www.wolframalpha.com/input/?i=tan^%28-1%29+%28-5%2F3%29

- anonymous

it will be most probably \[-\pi/3\]

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- anonymous

I was hoping Wolf would help me convert, but alas it appears not...
|dw:1342210050046:dw|

- anonymous

Actually that's fairly close annas
The actual value is -1.030376827... (radians)
-\(\frac{\pi}{3}\) is -1.047197551... (radians)

- anonymous

yes

- anonymous

Let me see if it takes it after I do the rest of the problem, if it does, you getz a cookie :-3

- anonymous

\[\frac{-\pi}{3} \rightarrow \frac{5\pi}{3}\] Yes?
And... (\(\large-\sqrt{34},\frac{2\pi }{3}\)) is the valid r<0 value, yes?

- anonymous

I don't know what they were expecting here. It's not quite a 3-4-5 triangle here, the 5 is on the opposite side, not the hypoteneuse

- anonymous

Proof that I can't make this stuff up, and that it's the only one for this part giving me issues:

- anonymous

eat cookies now !!!!

- anonymous

But it's not correct yet m'dear! ^_^

- anonymous

*meep*

- anonymous

yap thats why i said "eat cookies now !!!!"

- anonymous

*idea* I'm going to try 180/\(\pi\) to convert and see if I can recognize it

- anonymous

okey then goodluck

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