## agentx5 3 years ago Topic: $$Calculus \ 2$$, polar conversions Q: Identify name & Cartesian equation for: r = 2$$\tan \theta \sec \theta$$ Any graphing calculator can quickly show this is a parabola the one I've sketched below, but I'm trying to understand the process here. These are the facts I know of: $$r=\sqrt{x^2+y^2}$$ $$\theta = \tan^{-1}(\frac{y}{x})$$ x = r cos θ y = r sin θ What's the trick here? Can somebody show me? (I'd be more than happy to give out a medal if you can do so) There are a few other problems related to this one I'm working on so a technique to be learned is the goa

1. agentx5

$\large \sqrt{x^2+y^2}=\tan(\tan^{-1}\frac{y}{x})\sec(\tan^{-1}\frac{y}{x})$ But then um... lol what? |dw:1342214986994:dw|

2. myko

|dw:1342215821623:dw|

3. agentx5

Omg that was it?! D-: Good work @myko