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agentx5

  • 2 years ago

Topic: \(Calculus \ 2\), polar conversions Q: Identify name & Cartesian equation for: r = 2\(\tan \theta \sec \theta\) Any graphing calculator can quickly show this is a parabola the one I've sketched below, but I'm trying to understand the process here. These are the facts I know of: \(r=\sqrt{x^2+y^2}\) \(\theta = \tan^{-1}(\frac{y}{x})\) x = r cos θ y = r sin θ What's the trick here? Can somebody show me? (I'd be more than happy to give out a medal if you can do so) There are a few other problems related to this one I'm working on so a technique to be learned is the goa

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  1. agentx5
    • 2 years ago
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    \[\large \sqrt{x^2+y^2}=\tan(\tan^{-1}\frac{y}{x})\sec(\tan^{-1}\frac{y}{x})\] But then um... lol what? |dw:1342214986994:dw|

  2. myko
    • 2 years ago
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    |dw:1342215821623:dw|

  3. agentx5
    • 2 years ago
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    Omg that was it?! D-: Good work @myko

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