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Syl_Z

  • 3 years ago

An antiderivative of 3x^2/(2x^3-5) is:

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  1. hba
    • 3 years ago
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    take its integral

  2. slaaibak
    • 3 years ago
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    \[3x^2 \over 2x^3 - 5\] ?

  3. slaaibak
    • 3 years ago
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    Integrate by substitution.

  4. Andresfon12
    • 3 years ago
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    is look a quotant rule to me

  5. slaaibak
    • 3 years ago
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    no. it's integration, not differentiation

  6. campbell_st
    • 3 years ago
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    this is a log function let u = 2x^3 - 5 du/dx = 6x^2 1/2 du = 3x^2 so you are finding the antiderivative of \[\frac{1}{2} \int\limits \frac{du}{u} = \frac{1}{2} \ln( u) + c\]

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