Syl_Z
An antiderivative of 3x^2/(2x^3-5) is:
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hba
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take its integral
slaaibak
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\[3x^2 \over 2x^3 - 5\] ?
slaaibak
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Integrate by substitution.
Andresfon12
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is look a quotant rule to me
slaaibak
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no. it's integration, not differentiation
campbell_st
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this is a log function
let u = 2x^3 - 5 du/dx = 6x^2 1/2 du = 3x^2
so you are finding the antiderivative of
\[\frac{1}{2} \int\limits \frac{du}{u} = \frac{1}{2} \ln( u) + c\]