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jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
cmn fast
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
\[1/2\log_{2}x=1/3 \log_{2}y 1\] can you please simplfy
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
\[\log_{2}{x^2}=\log_{2}{(y1)^3} \]now it is clear that \[x^2=(y1)^3\]so now solve the equation & gt ur answer:)
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
and i use the property\[\frac{1}{e}\log_{b}{a}=\log_{b}{a^e} \]
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
can u do it from here @aceace ????
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
i dont really get the formula thing and i dont think i can do it...
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
k! i give u the solution
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
using the identity\[(xy)^3=x^3y^33x^2y3xy^2\]
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
so,\[x^2=y^31^33y^213y1^2\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
i think the 1 may be separate because that is the wrong answer...
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
@jiteshmeghwal9 formula should be: \[\large e.Log_ba = Log_b(a)^e\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
what is that formula for?
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
This is known as Power rule in Logarithms.. For example: \[Log(x  1)^2 \implies 2.Log(x1)\] Or, \[2.Log(x1) \implies Log(x1)^2\]
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
i meant if \[\LARGE{\log_{a^e}{b}=1/e \log_{a}{b}}\]then it will be\[\LARGE{\log_{a}{b^e} }\]
 2 years ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
so i m correct
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.2
you are asked to simplify \[\frac{1}{2}\log _{2}(x) = \frac{1}{3}\log _{2}(y 1)\] multiply both sides by 3 \[\log_{2}(y 1) = \frac{3}{2}\log(x)\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
ok.... that doesn't solve my problem...
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.2
now multiply both sides by 2 \[2\log _{2}(y 1) = 3\log_{2}(x)\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
i think that the 1 is separate from teh log on the right hand side...
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
that is wrong
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{2}\log_2x=\frac{1}{3}\log_2y−1\] \[\frac{1}{2}\log_2x + 1=\frac{1}{3}\log_2y\] \[\large \log_2(x)^\frac{1}{2} + Log_22 = Log_2(y)^\frac{1}{3}\] \[\large Log_2(2\sqrt{x}) = Log_2(\sqrt[3]{y})\] \[\Large 2 \times \sqrt{x} = \sqrt[3]{y}\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
that is what i got @waterineyes but the answer was different
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
What is the answer tell me??
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
it was...\[64x^{3}=y^{2}\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
Yeah I got it...
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
Before doing that I want to tell that: \[largeLog_2 64 = 6\]
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE (2\sqrt{x})^6 = 64x^{3}\] \[\LARGE (\sqrt[3]{y})^6 = y^2\] The answer you got IS correct. Just a different form.
 2 years ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{2}\log_2x=\frac{1}{3}\log_2y−1\] \[\frac{1}{2}\log_2x + 1=\frac{1}{3}\log_2y\] \[3\log_2x + 6= 2\log_2y\] \[\large \log_2x^3 + Log_264= \log_2y^2\] \[64x^3 = y^2\]
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.2
here is the solution \[\frac{1}{2}\log_{2}(x) + log_{2}(2) = \frac{1}{3}\log_{2}(y)\] multiply every term by 6 \[3\log_{2}(x) + 6\log_{2}(2) = 2\log_{2}(y)\] then \[Log_{2}(2^6x^3) = y^2\] raise to the power of 2 \[64x^3 = y^2\]
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
what is large LOG?
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
what does it mean?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
here is a constant source of confusion since log is a function it is really best to write \(\log(x)\) rather than \(\log x\)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
many (in fact maybe most) texts do not do this, but it would clear up the difference, for example, between \(\log(x+1)\)and \(\log (x) + 1\) then gets obscured when you simply write \(\log x + 1\)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i am assuming the problem is \[\frac{1}{2}\log(x)=\frac{1}{3}\log(y1)\] but it is hard to know from the way it is written
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.0
ok but what is a large log? as seen above
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
who knows?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
whatever it is, if the problem is the one i wrote you can multiply both sides by 6 and get \[3\log(x)=2\log(y1)\] \[\log(x^3)=\log((y1)^2)\] and so \[x^3=(y1)^2\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if was something else, say \[\frac{1}{2}\log(x)=\frac{1}{3}\log(y)  1\] then proceed as @campbell_st above
 2 years ago

Wired Group TitleBest ResponseYou've already chosen the best response.0
@aceace Large Log isn't a mathematical term. @waterineyes was trying to make the text bigger using a LaTeX markup command. Looks like a slash was missing, that's all.
 2 years ago
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