Delete
Share
This Question is Closed
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342256143778:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Try by rationalization process...
georgeblue22
Best Response
You've already chosen the best response.
1
|dw:1342256275514:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Multiply and divide both the sides by:
\[\sqrt{x+4}-\sqrt{x -3}\]
pratu043
Best Response
You've already chosen the best response.
1
You mean multiply by
\[(\sqrt{x+4} - \sqrt{x-3})/(\sqrt{x+4} - \sqrt{x-3})\]
waterineyes
Best Response
You've already chosen the best response.
1
Yes...
ganeshie8
Best Response
You've already chosen the best response.
0
check @georgeblue22 once.. its very simple
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342256415787:dw|
ganeshie8
Best Response
You've already chosen the best response.
0
i mean check @georgeblue22 reply once
waterineyes
Best Response
You've already chosen the best response.
1
No no don't do this...
pratu043
Best Response
You've already chosen the best response.
1
I don't understand @georgeblue22's reply.
waterineyes
Best Response
You've already chosen the best response.
1
just do what @georgeblue22 said..
I was thinking it as an expression but it is an equation..
I forgot to see there 1 on right hand side...
TheViper
Best Response
You've already chosen the best response.
1
\[\Huge{\color{gold}{\star \star}{\color{orange}{\text{Rationlise}}}}\]
TheViper
Best Response
You've already chosen the best response.
1
best hint
pratu043
Best Response
You've already chosen the best response.
1
Oh yes, he brought the denominator to the other side.
TheViper
Best Response
You've already chosen the best response.
1
yes @pratu043
waterineyes
Best Response
You've already chosen the best response.
1
See, multiply both the sides by : \(\sqrt{x+4}+\sqrt{x -3}\)..
pratu043
Best Response
You've already chosen the best response.
1
That will help to get of the square root on the left side.
TheViper
Best Response
You've already chosen the best response.
1
Understood @pratu043 ???
:)
waterineyes
Best Response
You've already chosen the best response.
1
You will left with only one square root term.... after solving..
pratu043
Best Response
You've already chosen the best response.
1
Left side will be:
|dw:1342256668499:dw|
waterineyes
Best Response
You've already chosen the best response.
1
No you are doing wrong..
pratu043
Best Response
You've already chosen the best response.
1
What's the mistake?
georgeblue22
Best Response
You've already chosen the best response.
1
|dw:1342256752422:dw|
Aditi_Singh
Best Response
You've already chosen the best response.
0
Did you try squaring on both the sides ?
waterineyes
Best Response
You've already chosen the best response.
1
See show me what you get after multiply the term I said above...
Do it slowly...
pratu043
Best Response
You've already chosen the best response.
1
Which term?
pratu043
Best Response
You've already chosen the best response.
1
So 7 = sqrt(x + 4) + sqrt(x - 3).
waterineyes
Best Response
You've already chosen the best response.
1
\[\frac{(\sqrt{x+4} - \sqrt{x-3})}{(\sqrt{x+4} + \sqrt{x-3})} \times (\sqrt{x+4} + \sqrt{x-3}) = 1 \times (\sqrt{x+4} + \sqrt{x-3})\]
Now solve this..
waterineyes
Best Response
You've already chosen the best response.
1
You will be left with:
\[\sqrt{x+4}- \sqrt{x-3} = \sqrt{x+4} + \sqrt{x-3}\]
Now look it properly what is the term that is getting cancelling on both the sides???
pratu043
Best Response
You've already chosen the best response.
1
sqrt(x + 4).
waterineyes
Best Response
You've already chosen the best response.
1
Yes then cancel it and tell me what you are left with now..
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342257083455:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Can you bring them on one side now??
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342257134878:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Yes add them...
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342257180914:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Yes...
Have faith you are in a right direction..
Now squaring both the sides what will you get??
TheViper
Best Response
You've already chosen the best response.
1
sqaure both sides @pratu043
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342257244043:dw|
waterineyes
Best Response
You've already chosen the best response.
1
And then put the brackets = 0 and find x from here..
pratu043
Best Response
You've already chosen the best response.
1
|dw:1342257276476:dw|
waterineyes
Best Response
You've already chosen the best response.
1
Yes..
You are right...
TheViper
Best Response
You've already chosen the best response.
1
yes @pratu043 u got it ;)
deserve a medal ;)
pratu043
Best Response
You've already chosen the best response.
1
Thanks!!!
TheViper
Best Response
You've already chosen the best response.
1
yw ;)
waterineyes
Best Response
You've already chosen the best response.
1
See @pratu043 if we are given with:
\[\large (x-1)(y-2) = 0\]
then you can do directly this:
\[(x - 1) =0 \quad and \quad (y - 2) = 0\]
Getting???
waterineyes
Best Response
You've already chosen the best response.
1
So at the end we are left with:
\[4(x-3) = 0\]
As \(4 \ne 0\)
So,
You can put directly:
\[(x-3) = 0\]
\[x = 3\]
pratu043
Best Response
You've already chosen the best response.
1
Oh I see .... I never knew that.
waterineyes
Best Response
You've already chosen the best response.
1
But this is possible in case we have 0 in right hand side..
Be careful...