Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

← 55 members online
  • 0 replying
  • 0 viewing

pratu043 Group Title

Find x.

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342256143778:dw|

    • 2 years ago
  2. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Try by rationalization process...

    • 2 years ago
  3. georgeblue22 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342256275514:dw|

    • 2 years ago
  4. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Multiply and divide both the sides by: \[\sqrt{x+4}-\sqrt{x -3}\]

    • 2 years ago
  5. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You mean multiply by \[(\sqrt{x+4} - \sqrt{x-3})/(\sqrt{x+4} - \sqrt{x-3})\]

    • 2 years ago
  6. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes...

    • 2 years ago
  7. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    check @georgeblue22 once.. its very simple

    • 2 years ago
  8. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342256415787:dw|

    • 2 years ago
  9. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i mean check @georgeblue22 reply once

    • 2 years ago
  10. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    No no don't do this...

    • 2 years ago
  11. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I don't understand @georgeblue22's reply.

    • 2 years ago
  12. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    just do what @georgeblue22 said.. I was thinking it as an expression but it is an equation.. I forgot to see there 1 on right hand side...

    • 2 years ago
  13. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\Huge{\color{gold}{\star \star}{\color{orange}{\text{Rationlise}}}}\]

    • 2 years ago
  14. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    best hint

    • 2 years ago
  15. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh yes, he brought the denominator to the other side.

    • 2 years ago
  16. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes @pratu043

    • 2 years ago
  17. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    See, multiply both the sides by : \(\sqrt{x+4}+\sqrt{x -3}\)..

    • 2 years ago
  18. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    That will help to get of the square root on the left side.

    • 2 years ago
  19. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Understood @pratu043 ??? :)

    • 2 years ago
  20. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You will left with only one square root term.... after solving..

    • 2 years ago
  21. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Left side will be: |dw:1342256668499:dw|

    • 2 years ago
  22. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    No you are doing wrong..

    • 2 years ago
  23. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    What's the mistake?

    • 2 years ago
  24. georgeblue22 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342256752422:dw|

    • 2 years ago
  25. Aditi_Singh Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Did you try squaring on both the sides ?

    • 2 years ago
  26. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    See show me what you get after multiply the term I said above... Do it slowly...

    • 2 years ago
  27. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Which term?

    • 2 years ago
  28. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So 7 = sqrt(x + 4) + sqrt(x - 3).

    • 2 years ago
  29. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{(\sqrt{x+4} - \sqrt{x-3})}{(\sqrt{x+4} + \sqrt{x-3})} \times (\sqrt{x+4} + \sqrt{x-3}) = 1 \times (\sqrt{x+4} + \sqrt{x-3})\] Now solve this..

    • 2 years ago
  30. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You will be left with: \[\sqrt{x+4}- \sqrt{x-3} = \sqrt{x+4} + \sqrt{x-3}\] Now look it properly what is the term that is getting cancelling on both the sides???

    • 2 years ago
  31. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sqrt(x + 4).

    • 2 years ago
  32. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes then cancel it and tell me what you are left with now..

    • 2 years ago
  33. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342257083455:dw|

    • 2 years ago
  34. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Can you bring them on one side now??

    • 2 years ago
  35. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342257134878:dw|

    • 2 years ago
  36. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes add them...

    • 2 years ago
  37. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342257180914:dw|

    • 2 years ago
  38. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes... Have faith you are in a right direction.. Now squaring both the sides what will you get??

    • 2 years ago
  39. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sqaure both sides @pratu043

    • 2 years ago
  40. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342257244043:dw|

    • 2 years ago
  41. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    And then put the brackets = 0 and find x from here..

    • 2 years ago
  42. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342257276476:dw|

    • 2 years ago
  43. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes.. You are right...

    • 2 years ago
  44. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes @pratu043 u got it ;) deserve a medal ;)

    • 2 years ago
  45. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Thanks!!!

    • 2 years ago
  46. TheViper Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yw ;)

    • 2 years ago
  47. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    See @pratu043 if we are given with: \[\large (x-1)(y-2) = 0\] then you can do directly this: \[(x - 1) =0 \quad and \quad (y - 2) = 0\] Getting???

    • 2 years ago
  48. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So at the end we are left with: \[4(x-3) = 0\] As \(4 \ne 0\) So, You can put directly: \[(x-3) = 0\] \[x = 3\]

    • 2 years ago
  49. pratu043 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh I see .... I never knew that.

    • 2 years ago
  50. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    But this is possible in case we have 0 in right hand side.. Be careful...

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 β†’ View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • βœ” You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.