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virtus
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find the no. of ways in which 8 people can be seated at 2 round tables with 4 people sitting at each table?
 2 years ago
 2 years ago
virtus Group Title
find the no. of ways in which 8 people can be seated at 2 round tables with 4 people sitting at each table?
 2 years ago
 2 years ago

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Hashir Group TitleBest ResponseYou've already chosen the best response.0
acually its like ... choose four people ...then arrange them .... permutaion means choosing and aranging
 2 years ago

Hashir Group TitleBest ResponseYou've already chosen the best response.0
that dot means multiplty
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
why does the answer in my solution book say this : 7x6x5x3x2x1x2
 2 years ago

Hashir Group TitleBest ResponseYou've already chosen the best response.0
wait a sec .... let me take a look at question again
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
WAIT I HAVE A WAY
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
@hba having epiphanies are we?
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
IF UR ASKED OF A ROW THEN n! IF UR ASKED ABOUT A CIRCLE OR ROUND ITS (n1)! AND IF ITS A NECKLACE OR GARLAND ITS 1/2(n1)!
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
IN UR CASE IT WOULD BE (81)! =7!
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
AND 2 TABLES SO U MULTIPLY IT BY 2 THEN
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
Remember that a circular permutation is (n – 1)! Break the seating process into "activities" like this: 1) Choose the people who are seated at each table. C(8,4 = 8•7•6•5/4•3•2•1 = 70). When you choose for 1 table the other four automatically go to the other table. 2) Arrange the 4 people at table A: (4 – 1)! = 3! = 6 3) Arrange the 4 people at table B. Also 3! =6 So answer is C(8,4)•3!•3! = 70•6•6 = 2520
 2 years ago

Hashir Group TitleBest ResponseYou've already chosen the best response.0
he copied it from somewhere :D
 2 years ago

Hashir Group TitleBest ResponseYou've already chosen the best response.0
anyway ... nice work @hba :D
 2 years ago

hba Group TitleBest ResponseYou've already chosen the best response.2
You are free: to Share — to copy, distribute and transmit the work to Remix — to adapt the work
 2 years ago

virtus Group TitleBest ResponseYou've already chosen the best response.0
hey @hba so you used combinations and not only permutations for this questions?
 2 years ago
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