anonymous
  • anonymous
find the no. of ways in which 8 people can be seated at 2 round tables with 4 people sitting at each table?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
got it???
anonymous
  • anonymous
acually its like ... choose four people ...then arrange them .... permutaion means choosing and aranging
hba
  • hba
36

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anonymous
  • anonymous
that dot means multiplty
anonymous
  • anonymous
why does the answer in my solution book say this : 7x6x5x3x2x1x2
anonymous
  • anonymous
wait a sec .... let me take a look at question again
hba
  • hba
WAIT I HAVE A WAY
anonymous
  • anonymous
@hba having epiphanies are we?
hba
  • hba
IF UR ASKED OF A ROW THEN n! IF UR ASKED ABOUT A CIRCLE OR ROUND ITS (n-1)! AND IF ITS A NECKLACE OR GARLAND ITS 1/2(n-1)!
hba
  • hba
IN UR CASE IT WOULD BE (8-1)! =7!
hba
  • hba
AND 2 TABLES SO U MULTIPLY IT BY 2 THEN
anonymous
  • anonymous
naaaa
hba
  • hba
Remember that a circular permutation is (n – 1)! Break the seating process into "activities" like this: 1) Choose the people who are seated at each table. C(8,4 = 8•7•6•5/4•3•2•1 = 70). When you choose for 1 table the other four automatically go to the other table. 2) Arrange the 4 people at table A: (4 – 1)! = 3! = 6 3) Arrange the 4 people at table B. Also 3! =6 So answer is C(8,4)•3!•3! = 70•6•6 = 2520
anonymous
  • anonymous
he copied it from somewhere :D
anonymous
  • anonymous
anyway ... nice work @hba :D
hba
  • hba
You are free: to Share — to copy, distribute and transmit the work to Remix — to adapt the work
anonymous
  • anonymous
^^ LOL
anonymous
  • anonymous
hey @hba so you used combinations and not only permutations for this questions?
hba
  • hba
yeah

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