anonymous
  • anonymous
Integral of (x^3.^root(4x-x^2) dx with integral limits 0,4 Integral of x^4/(1+x^2)^4 dx with integral limits 0,5 pls giv me solution for above 2 questns in detailled steps
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Mimi_x3
  • Mimi_x3
\[\int x^{3}\sqrt{x^{2}-4} dx\]
Mimi_x3
  • Mimi_x3
Is that the integral?
Mimi_x3
  • Mimi_x3
I mean: \[\large \int\limits x^{3}\sqrt{4x-x^{2}} dx\]?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yes limits given in questn
anonymous
  • anonymous
Pls giv me slution in steps as i need to note it
lgbasallote
  • lgbasallote
i think you're supposed to do completing the swuare here
Mimi_x3
  • Mimi_x3
well, it's completing the square first then trig-sub. Why not you try it; then me typing the solution for you?
Mimi_x3
  • Mimi_x3
than me*
anonymous
  • anonymous
I dont know how to do,pls giv me steps
anonymous
  • anonymous
\[4x - x^2 = -(x^2 - 4x)\]\[= -(x^2 - 4x) - 4 + 4\]\[= -(x^2 - 4x + 4) + 4\]\[= 4 - (x^2 - 4x + 4)\]\[= 4 - (x - 2)^2\]\[\int\limits x^3 \sqrt{4x - x^2}dx = \int\limits x^3 \sqrt{4 - (x - 2)^2} dx\]there i already completed the square for you, just do trig subs and you'll be fine

Looking for something else?

Not the answer you are looking for? Search for more explanations.