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Eight keys are placed on a key ring. How many different arrangements are possible if they are all different
 one year ago
 one year ago
Eight keys are placed on a key ring. How many different arrangements are possible if they are all different
 one year ago
 one year ago

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IllasMcKayBest ResponseYou've already chosen the best response.0
just wait my Friend
 one year ago

IllasMcKayBest ResponseYou've already chosen the best response.0
dw:1342271877443:dw then 8 factorial as @sauravshakya
 one year ago

virtusBest ResponseYou've already chosen the best response.0
my solution book says the answer is 7!/2
 one year ago

virtusBest ResponseYou've already chosen the best response.0
@myko where does the 2 come from?
 one year ago

mykoBest ResponseYou've already chosen the best response.3
dw:1342272266287:dw dw:1342272292346:dw is the same in this case
 one year ago

mykoBest ResponseYou've already chosen the best response.3
no, you right. The right answer is 7!/2
 one year ago

virtusBest ResponseYou've already chosen the best response.0
yes i thought so, because it is (n1)!
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
The total number of n objects, arranged in a circle which can be flipped over without making a new arrangement is: \[\frac{(n1)!}{2}\]
 one year ago

mykoBest ResponseYou've already chosen the best response.3
it is (n1)! and not n!, because there is no reference point. The reference point is the first key you put, so it's has to be rested from the total number of left posibilties. It is later devided by 2, becouse the ring can flip, so symetric permutations become the same
 one year ago

virtusBest ResponseYou've already chosen the best response.0
btw @myko does this rule apply to sitting in a circle arrangements
 one year ago
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