anonymous
  • anonymous
Eight keys are placed on a key ring. How many different arrangements are possible if they are all different
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Pairs or ....
anonymous
  • anonymous
what do you mean?
anonymous
  • anonymous
just wait my Friend

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More answers

anonymous
  • anonymous
8 factorial
anonymous
  • anonymous
|dw:1342271877443:dw| then 8 factorial as @sauravshakya
anonymous
  • anonymous
my solution book says the answer is 7!/2
anonymous
  • anonymous
@myko where does the 2 come from?
anonymous
  • anonymous
|dw:1342272266287:dw| |dw:1342272292346:dw| is the same in this case
anonymous
  • anonymous
no, you right. The right answer is 7!/2
anonymous
  • anonymous
yes i thought so, because it is (n-1)!
anonymous
  • anonymous
The total number of n objects, arranged in a circle which can be flipped over without making a new arrangement is: \[\frac{(n-1)!}{2}\]
anonymous
  • anonymous
thank you@mukushla
anonymous
  • anonymous
it is (n-1)! and not n!, because there is no reference point. The reference point is the first key you put, so it's has to be rested from the total number of left posibilties. It is later devided by 2, becouse the ring can flip, so symetric permutations become the same
anonymous
  • anonymous
btw @myko does this rule apply to sitting in a circle arrangements

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