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Eight keys are placed on a key ring. How many different arrangements are possible if they are all different

Mathematics
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Pairs or ....
what do you mean?
just wait my Friend

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Other answers:

8 factorial
|dw:1342271877443:dw| then 8 factorial as @sauravshakya
my solution book says the answer is 7!/2
@myko where does the 2 come from?
|dw:1342272266287:dw| |dw:1342272292346:dw| is the same in this case
no, you right. The right answer is 7!/2
yes i thought so, because it is (n-1)!
The total number of n objects, arranged in a circle which can be flipped over without making a new arrangement is: \[\frac{(n-1)!}{2}\]
thank you@mukushla
it is (n-1)! and not n!, because there is no reference point. The reference point is the first key you put, so it's has to be rested from the total number of left posibilties. It is later devided by 2, becouse the ring can flip, so symetric permutations become the same
btw @myko does this rule apply to sitting in a circle arrangements

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