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anonymous
 4 years ago
Eight keys are placed on a key ring. How many different arrangements are possible if they are all different
anonymous
 4 years ago
Eight keys are placed on a key ring. How many different arrangements are possible if they are all different

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1342271877443:dw then 8 factorial as @sauravshakya

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my solution book says the answer is 7!/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@myko where does the 2 come from?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1342272266287:dw dw:1342272292346:dw is the same in this case

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, you right. The right answer is 7!/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i thought so, because it is (n1)!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The total number of n objects, arranged in a circle which can be flipped over without making a new arrangement is: \[\frac{(n1)!}{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is (n1)! and not n!, because there is no reference point. The reference point is the first key you put, so it's has to be rested from the total number of left posibilties. It is later devided by 2, becouse the ring can flip, so symetric permutations become the same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0btw @myko does this rule apply to sitting in a circle arrangements
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