Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

virtus Group Title

Eight keys are placed on a key ring. How many different arrangements are possible if they are all different

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. IllasMcKay Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Pairs or ....

    • 2 years ago
  2. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    what do you mean?

    • 2 years ago
  3. IllasMcKay Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    just wait my Friend

    • 2 years ago
  4. sauravshakya Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    8 factorial

    • 2 years ago
  5. IllasMcKay Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1342271877443:dw| then 8 factorial as @sauravshakya

    • 2 years ago
  6. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    my solution book says the answer is 7!/2

    • 2 years ago
  7. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @myko where does the 2 come from?

    • 2 years ago
  8. myko Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    |dw:1342272266287:dw| |dw:1342272292346:dw| is the same in this case

    • 2 years ago
  9. myko Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    no, you right. The right answer is 7!/2

    • 2 years ago
  10. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yes i thought so, because it is (n-1)!

    • 2 years ago
  11. mukushla Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    The total number of n objects, arranged in a circle which can be flipped over without making a new arrangement is: \[\frac{(n-1)!}{2}\]

    • 2 years ago
  12. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you@mukushla

    • 2 years ago
  13. myko Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    it is (n-1)! and not n!, because there is no reference point. The reference point is the first key you put, so it's has to be rested from the total number of left posibilties. It is later devided by 2, becouse the ring can flip, so symetric permutations become the same

    • 2 years ago
  14. virtus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    btw @myko does this rule apply to sitting in a circle arrangements

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.