anonymous
  • anonymous
PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
HELP please explain how :)
1 Attachment
anonymous
  • anonymous
could I get any Idea about computer science? I have some project work this week!!
anonymous
  • anonymous
Earth-Space Science??

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More answers

hba
  • hba
1)-7
hba
  • hba
2)2\[\sqrt{11}\]
anonymous
  • anonymous
you mean 3√11 or 2√22 ????
hba
  • hba
|dw:1342277961301:dw|
anonymous
  • anonymous
k #3 ?? :)
anonymous
  • anonymous
-7 is answer
anonymous
  • anonymous
friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]
anonymous
  • anonymous
awesome i got that one PLEASE continue muhammad9t5
anonymous
  • anonymous
yes did you understand?
anonymous
  • anonymous
yes :) the other ones aren't that simple though:(
anonymous
  • anonymous
if yes then please dont forget to click on best answer to vote me.
anonymous
  • anonymous
thanks/.... @Ashley99
anonymous
  • anonymous
no prob PLEASE keep going muhammad9t5
anonymous
  • anonymous
muhammad9t5 ??????
anonymous
  • anonymous
yes whats up?
anonymous
  • anonymous
friend thats your answer.....
anonymous
  • anonymous
can you PLEASE help me w/ the other probs too??
anonymous
  • anonymous
you explain things very well :)
anonymous
  • anonymous
yes friend i will do my best to help you more..
anonymous
  • anonymous
friend whats your other question?
anonymous
  • anonymous
click the attachment it's #2
anonymous
  • anonymous
friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...
anonymous
  • anonymous
sorry \[3\sqrt{11}\]
anonymous
  • anonymous
ok that's wat i thought but i doubt myself :)
anonymous
  • anonymous
#3 Please (you rock)
anonymous
  • anonymous
friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.
anonymous
  • anonymous
another check i'm kinda iffy about this lesson it's √3y^3
anonymous
  • anonymous
#4 I think is- 13p^3√p-2p√p yes or no
anonymous
  • anonymous
muhammad9t5 ??
anonymous
  • anonymous
wait friend.
anonymous
  • anonymous
you still there muhammad9t5 ??
anonymous
  • anonymous
yes i am
anonymous
  • anonymous
did you get the Q?
anonymous
  • anonymous
no i didnt... but i will do it later.
anonymous
  • anonymous
@Loujoelou i need your help w/
anonymous
  • anonymous
PLEASE I REALLY NEED HELP NOW
anonymous
  • anonymous
@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY
anonymous
  • anonymous
K I just opened the document.
anonymous
  • anonymous
no not the stuff in the doc the message above!!!
anonymous
  • anonymous
Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?
anonymous
  • anonymous
1st term yep
anonymous
  • anonymous
What about the 2nd?
anonymous
  • anonymous
nope?
anonymous
  • anonymous
Yes, you're correct. Do you know how to simplify it?
anonymous
  • anonymous
friend can we move to 5th??
anonymous
  • anonymous
@muhammad9t5 sure
anonymous
  • anonymous
?
anonymous
  • anonymous
@Loujoelou eh......... please explain
anonymous
  • anonymous
\[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.
anonymous
  • anonymous
Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]
anonymous
  • anonymous
@muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways
anonymous
  • anonymous
|dw:1342281716312:dw|
anonymous
  • anonymous
Now for the 3rd term. \[-5 \sqrt{18x}\] Factors of 18=2*3*3 |dw:1342281717942:dw|
anonymous
  • anonymous
@Loujoelou ????
anonymous
  • anonymous
@muhammad9t5 PLEASE this is the last Q
anonymous
  • anonymous
\[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
ITS -5 not -15!!!!!!!!
anonymous
  • anonymous
\[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is
anonymous
  • anonymous
the first 2 terms are right but the last is -15 sqrt(2x)
anonymous
  • anonymous
That's what I wrote.
anonymous
  • anonymous
i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver
anonymous
  • anonymous
No prob. :)
anonymous
  • anonymous
what is the final answer then?
anonymous
  • anonymous
@Loujoelou PLEASE ANSWER ME THEN I"M DONE
anonymous
  • anonymous
Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.
anonymous
  • anonymous
but it's 2x not just 2
anonymous
  • anonymous
3+2x-15
anonymous
  • anonymous
oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.
anonymous
  • anonymous
so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]
anonymous
  • anonymous
????
anonymous
  • anonymous
No
anonymous
  • anonymous
GREAT *sigh* 1 assignment down 16 more to go
anonymous
  • anonymous
17 MORE!!!
anonymous
  • anonymous
Darn my internet connection isn't working :/ g2g sorry

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