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Ashley99

  • 3 years ago

PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

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  1. Ashley99
    • 3 years ago
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    HELP please explain how :)

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  2. WONDEMU
    • 3 years ago
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    could I get any Idea about computer science? I have some project work this week!!

  3. Ashley99
    • 3 years ago
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    Earth-Space Science??

  4. hba
    • 3 years ago
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    1)-7

  5. hba
    • 3 years ago
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    2)2\[\sqrt{11}\]

  6. Ashley99
    • 3 years ago
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    you mean 3√11 or 2√22 ????

  7. hba
    • 3 years ago
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    |dw:1342277961301:dw|

  8. Ashley99
    • 3 years ago
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    k #3 ?? :)

  9. muhammad9t5
    • 3 years ago
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    -7 is answer

  10. muhammad9t5
    • 3 years ago
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    friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]

  11. Ashley99
    • 3 years ago
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    awesome i got that one PLEASE continue muhammad9t5

  12. muhammad9t5
    • 3 years ago
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    yes did you understand?

  13. Ashley99
    • 3 years ago
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    yes :) the other ones aren't that simple though:(

  14. muhammad9t5
    • 3 years ago
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    if yes then please dont forget to click on best answer to vote me.

  15. muhammad9t5
    • 3 years ago
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    thanks/.... @Ashley99

  16. Ashley99
    • 3 years ago
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    no prob PLEASE keep going muhammad9t5

  17. Ashley99
    • 3 years ago
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    muhammad9t5 ??????

  18. muhammad9t5
    • 3 years ago
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    yes whats up?

  19. muhammad9t5
    • 3 years ago
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    friend thats your answer.....

  20. Ashley99
    • 3 years ago
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    can you PLEASE help me w/ the other probs too??

  21. Ashley99
    • 3 years ago
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    you explain things very well :)

  22. muhammad9t5
    • 3 years ago
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    yes friend i will do my best to help you more..

  23. muhammad9t5
    • 3 years ago
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    friend whats your other question?

  24. Ashley99
    • 3 years ago
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    click the attachment it's #2

  25. muhammad9t5
    • 3 years ago
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    friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...

  26. muhammad9t5
    • 3 years ago
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    sorry \[3\sqrt{11}\]

  27. Ashley99
    • 3 years ago
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    ok that's wat i thought but i doubt myself :)

  28. Ashley99
    • 3 years ago
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    #3 Please (you rock)

  29. muhammad9t5
    • 3 years ago
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    friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

  30. Ashley99
    • 3 years ago
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    another check i'm kinda iffy about this lesson it's √3y^3

  31. Ashley99
    • 3 years ago
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    #4 I think is- 13p^3√p-2p√p yes or no

  32. Ashley99
    • 3 years ago
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    muhammad9t5 ??

  33. muhammad9t5
    • 3 years ago
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    wait friend.

  34. Ashley99
    • 3 years ago
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    you still there muhammad9t5 ??

  35. muhammad9t5
    • 3 years ago
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    yes i am

  36. Ashley99
    • 3 years ago
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    did you get the Q?

  37. muhammad9t5
    • 3 years ago
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    no i didnt... but i will do it later.

  38. Ashley99
    • 3 years ago
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    @Loujoelou i need your help w/

  39. Ashley99
    • 3 years ago
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    PLEASE I REALLY NEED HELP NOW

  40. Ashley99
    • 3 years ago
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    @Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY

  41. Loujoelou
    • 3 years ago
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    K I just opened the document.

  42. Ashley99
    • 3 years ago
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    no not the stuff in the doc the message above!!!

  43. Loujoelou
    • 3 years ago
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    Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

  44. Ashley99
    • 3 years ago
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    1st term yep

  45. Loujoelou
    • 3 years ago
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    What about the 2nd?

  46. Ashley99
    • 3 years ago
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    nope?

  47. Loujoelou
    • 3 years ago
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    Yes, you're correct. Do you know how to simplify it?

  48. muhammad9t5
    • 3 years ago
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    friend can we move to 5th??

  49. Ashley99
    • 3 years ago
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    @muhammad9t5 sure

  50. Loujoelou
    • 3 years ago
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    ?

  51. Ashley99
    • 3 years ago
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    @Loujoelou eh......... please explain

  52. muhammad9t5
    • 3 years ago
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    \[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.

  53. Loujoelou
    • 3 years ago
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    Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]

  54. Ashley99
    • 3 years ago
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    @muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways

  55. Ashley99
    • 3 years ago
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    |dw:1342281716312:dw|

  56. Loujoelou
    • 3 years ago
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    Now for the 3rd term. \[-5 \sqrt{18x}\] Factors of 18=2*3*3 |dw:1342281717942:dw|

  57. Ashley99
    • 3 years ago
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    @Loujoelou ????

  58. Ashley99
    • 3 years ago
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    @muhammad9t5 PLEASE this is the last Q

  59. Loujoelou
    • 3 years ago
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    \[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]

  60. Ashley99
    • 3 years ago
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    oh ok

  61. Ashley99
    • 3 years ago
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    ITS -5 not -15!!!!!!!!

  62. Loujoelou
    • 3 years ago
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    \[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is

  63. Ashley99
    • 3 years ago
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    the first 2 terms are right but the last is -15 sqrt(2x)

  64. Loujoelou
    • 3 years ago
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    That's what I wrote.

  65. Ashley99
    • 3 years ago
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    i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver

  66. Loujoelou
    • 3 years ago
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    No prob. :)

  67. Ashley99
    • 3 years ago
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    what is the final answer then?

  68. Ashley99
    • 3 years ago
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    @Loujoelou PLEASE ANSWER ME THEN I"M DONE

  69. Loujoelou
    • 3 years ago
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    Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.

  70. Ashley99
    • 3 years ago
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    but it's 2x not just 2

  71. Ashley99
    • 3 years ago
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    3+2x-15

  72. Loujoelou
    • 3 years ago
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    oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.

  73. Ashley99
    • 3 years ago
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    so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]

  74. Ashley99
    • 3 years ago
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    ????

  75. Loujoelou
    • 3 years ago
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    No

  76. Ashley99
    • 3 years ago
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    GREAT *sigh* 1 assignment down 16 more to go

  77. Ashley99
    • 3 years ago
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    17 MORE!!!

  78. Loujoelou
    • 3 years ago
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    Darn my internet connection isn't working :/ g2g sorry

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