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Ashley99

PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

  • one year ago
  • one year ago

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  1. Ashley99
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    HELP please explain how :)

    • one year ago
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  2. WONDEMU
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    could I get any Idea about computer science? I have some project work this week!!

    • one year ago
  3. Ashley99
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    Earth-Space Science??

    • one year ago
  4. hba
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    1)-7

    • one year ago
  5. hba
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    2)2\[\sqrt{11}\]

    • one year ago
  6. Ashley99
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    you mean 3√11 or 2√22 ????

    • one year ago
  7. hba
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    |dw:1342277961301:dw|

    • one year ago
  8. Ashley99
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    k #3 ?? :)

    • one year ago
  9. muhammad9t5
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    -7 is answer

    • one year ago
  10. muhammad9t5
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    friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]

    • one year ago
  11. Ashley99
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    awesome i got that one PLEASE continue muhammad9t5

    • one year ago
  12. muhammad9t5
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    yes did you understand?

    • one year ago
  13. Ashley99
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    yes :) the other ones aren't that simple though:(

    • one year ago
  14. muhammad9t5
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    if yes then please dont forget to click on best answer to vote me.

    • one year ago
  15. muhammad9t5
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    thanks/.... @Ashley99

    • one year ago
  16. Ashley99
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    no prob PLEASE keep going muhammad9t5

    • one year ago
  17. Ashley99
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    muhammad9t5 ??????

    • one year ago
  18. muhammad9t5
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    yes whats up?

    • one year ago
  19. muhammad9t5
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    friend thats your answer.....

    • one year ago
  20. Ashley99
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    can you PLEASE help me w/ the other probs too??

    • one year ago
  21. Ashley99
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    you explain things very well :)

    • one year ago
  22. muhammad9t5
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    yes friend i will do my best to help you more..

    • one year ago
  23. muhammad9t5
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    friend whats your other question?

    • one year ago
  24. Ashley99
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    click the attachment it's #2

    • one year ago
  25. muhammad9t5
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    friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...

    • one year ago
  26. muhammad9t5
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    sorry \[3\sqrt{11}\]

    • one year ago
  27. Ashley99
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    ok that's wat i thought but i doubt myself :)

    • one year ago
  28. Ashley99
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    #3 Please (you rock)

    • one year ago
  29. muhammad9t5
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    friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

    • one year ago
  30. Ashley99
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    another check i'm kinda iffy about this lesson it's √3y^3

    • one year ago
  31. Ashley99
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    #4 I think is- 13p^3√p-2p√p yes or no

    • one year ago
  32. Ashley99
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    muhammad9t5 ??

    • one year ago
  33. muhammad9t5
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    wait friend.

    • one year ago
  34. Ashley99
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    you still there muhammad9t5 ??

    • one year ago
  35. muhammad9t5
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    yes i am

    • one year ago
  36. Ashley99
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    did you get the Q?

    • one year ago
  37. muhammad9t5
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    no i didnt... but i will do it later.

    • one year ago
  38. Ashley99
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    @Loujoelou i need your help w/

    • one year ago
  39. Ashley99
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    PLEASE I REALLY NEED HELP NOW

    • one year ago
  40. Ashley99
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    @Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY

    • one year ago
  41. Loujoelou
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    K I just opened the document.

    • one year ago
  42. Ashley99
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    no not the stuff in the doc the message above!!!

    • one year ago
  43. Loujoelou
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    Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

    • one year ago
  44. Ashley99
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    1st term yep

    • one year ago
  45. Loujoelou
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    What about the 2nd?

    • one year ago
  46. Ashley99
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    nope?

    • one year ago
  47. Loujoelou
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    Yes, you're correct. Do you know how to simplify it?

    • one year ago
  48. muhammad9t5
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    friend can we move to 5th??

    • one year ago
  49. Ashley99
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    @muhammad9t5 sure

    • one year ago
  50. Loujoelou
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    ?

    • one year ago
  51. Ashley99
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    @Loujoelou eh......... please explain

    • one year ago
  52. muhammad9t5
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    \[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.

    • one year ago
  53. Loujoelou
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    Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]

    • one year ago
  54. Ashley99
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    @muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways

    • one year ago
  55. Ashley99
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    |dw:1342281716312:dw|

    • one year ago
  56. Loujoelou
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    Now for the 3rd term. \[-5 \sqrt{18x}\] Factors of 18=2*3*3 |dw:1342281717942:dw|

    • one year ago
  57. Ashley99
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    @Loujoelou ????

    • one year ago
  58. Ashley99
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    @muhammad9t5 PLEASE this is the last Q

    • one year ago
  59. Loujoelou
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    \[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]

    • one year ago
  60. Ashley99
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    oh ok

    • one year ago
  61. Ashley99
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    ITS -5 not -15!!!!!!!!

    • one year ago
  62. Loujoelou
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    \[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is

    • one year ago
  63. Ashley99
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    the first 2 terms are right but the last is -15 sqrt(2x)

    • one year ago
  64. Loujoelou
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    That's what I wrote.

    • one year ago
  65. Ashley99
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    i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver

    • one year ago
  66. Loujoelou
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    No prob. :)

    • one year ago
  67. Ashley99
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    what is the final answer then?

    • one year ago
  68. Ashley99
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    @Loujoelou PLEASE ANSWER ME THEN I"M DONE

    • one year ago
  69. Loujoelou
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    Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.

    • one year ago
  70. Ashley99
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    but it's 2x not just 2

    • one year ago
  71. Ashley99
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    3+2x-15

    • one year ago
  72. Loujoelou
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    oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.

    • one year ago
  73. Ashley99
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    so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]

    • one year ago
  74. Ashley99
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    ????

    • one year ago
  75. Loujoelou
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    No

    • one year ago
  76. Ashley99
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    GREAT *sigh* 1 assignment down 16 more to go

    • one year ago
  77. Ashley99
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    17 MORE!!!

    • one year ago
  78. Loujoelou
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    Darn my internet connection isn't working :/ g2g sorry

    • one year ago
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