Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Ashley99 Group Title

PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    HELP please explain how :)

    • 2 years ago
    1 Attachment
  2. WONDEMU Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    could I get any Idea about computer science? I have some project work this week!!

    • 2 years ago
  3. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Earth-Space Science??

    • 2 years ago
  4. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    1)-7

    • 2 years ago
  5. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2)2\[\sqrt{11}\]

    • 2 years ago
  6. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you mean 3√11 or 2√22 ????

    • 2 years ago
  7. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1342277961301:dw|

    • 2 years ago
  8. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    k #3 ?? :)

    • 2 years ago
  9. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    -7 is answer

    • 2 years ago
  10. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]

    • 2 years ago
  11. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    awesome i got that one PLEASE continue muhammad9t5

    • 2 years ago
  12. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes did you understand?

    • 2 years ago
  13. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes :) the other ones aren't that simple though:(

    • 2 years ago
  14. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    if yes then please dont forget to click on best answer to vote me.

    • 2 years ago
  15. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks/.... @Ashley99

    • 2 years ago
  16. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no prob PLEASE keep going muhammad9t5

    • 2 years ago
  17. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    muhammad9t5 ??????

    • 2 years ago
  18. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes whats up?

    • 2 years ago
  19. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend thats your answer.....

    • 2 years ago
  20. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    can you PLEASE help me w/ the other probs too??

    • 2 years ago
  21. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you explain things very well :)

    • 2 years ago
  22. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes friend i will do my best to help you more..

    • 2 years ago
  23. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend whats your other question?

    • 2 years ago
  24. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    click the attachment it's #2

    • 2 years ago
  25. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...

    • 2 years ago
  26. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry \[3\sqrt{11}\]

    • 2 years ago
  27. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ok that's wat i thought but i doubt myself :)

    • 2 years ago
  28. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    #3 Please (you rock)

    • 2 years ago
  29. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

    • 2 years ago
  30. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    another check i'm kinda iffy about this lesson it's √3y^3

    • 2 years ago
  31. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    #4 I think is- 13p^3√p-2p√p yes or no

    • 2 years ago
  32. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    muhammad9t5 ??

    • 2 years ago
  33. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wait friend.

    • 2 years ago
  34. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you still there muhammad9t5 ??

    • 2 years ago
  35. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes i am

    • 2 years ago
  36. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    did you get the Q?

    • 2 years ago
  37. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no i didnt... but i will do it later.

    • 2 years ago
  38. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Loujoelou i need your help w/

    • 2 years ago
  39. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    PLEASE I REALLY NEED HELP NOW

    • 2 years ago
  40. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY

    • 2 years ago
  41. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    K I just opened the document.

    • 2 years ago
  42. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no not the stuff in the doc the message above!!!

    • 2 years ago
  43. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

    • 2 years ago
  44. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    1st term yep

    • 2 years ago
  45. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    What about the 2nd?

    • 2 years ago
  46. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    nope?

    • 2 years ago
  47. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, you're correct. Do you know how to simplify it?

    • 2 years ago
  48. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    friend can we move to 5th??

    • 2 years ago
  49. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @muhammad9t5 sure

    • 2 years ago
  50. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

    • 2 years ago
  51. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Loujoelou eh......... please explain

    • 2 years ago
  52. muhammad9t5 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.

    • 2 years ago
  53. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]

    • 2 years ago
  54. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways

    • 2 years ago
  55. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1342281716312:dw|

    • 2 years ago
  56. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Now for the 3rd term. \[-5 \sqrt{18x}\] Factors of 18=2*3*3 |dw:1342281717942:dw|

    • 2 years ago
  57. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Loujoelou ????

    • 2 years ago
  58. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @muhammad9t5 PLEASE this is the last Q

    • 2 years ago
  59. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]

    • 2 years ago
  60. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh ok

    • 2 years ago
  61. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ITS -5 not -15!!!!!!!!

    • 2 years ago
  62. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is

    • 2 years ago
  63. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    the first 2 terms are right but the last is -15 sqrt(2x)

    • 2 years ago
  64. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    That's what I wrote.

    • 2 years ago
  65. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver

    • 2 years ago
  66. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    No prob. :)

    • 2 years ago
  67. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    what is the final answer then?

    • 2 years ago
  68. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @Loujoelou PLEASE ANSWER ME THEN I"M DONE

    • 2 years ago
  69. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.

    • 2 years ago
  70. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    but it's 2x not just 2

    • 2 years ago
  71. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    3+2x-15

    • 2 years ago
  72. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.

    • 2 years ago
  73. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]

    • 2 years ago
  74. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ????

    • 2 years ago
  75. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    No

    • 2 years ago
  76. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    GREAT *sigh* 1 assignment down 16 more to go

    • 2 years ago
  77. Ashley99 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    17 MORE!!!

    • 2 years ago
  78. Loujoelou Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Darn my internet connection isn't working :/ g2g sorry

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.