Ashley99
PLEASE SOLVE AND EXPLAIN
Adding and Subtracting Radical Expressions
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Ashley99
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HELP please explain how :)
WONDEMU
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could I get any Idea about computer science? I have some project work this week!!
Ashley99
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Earth-Space Science??
hba
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1)-7
hba
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2)2\[\sqrt{11}\]
Ashley99
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you mean 3√11 or 2√22
????
hba
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|dw:1342277961301:dw|
Ashley99
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k #3
??
:)
muhammad9t5
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-7 is answer
muhammad9t5
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friend you dont count x in that just count the numbers. like below
\[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\]
\[3\sqrt{7}-3\sqrt{7}-7\]
\[-7\]
Ashley99
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awesome i got that one PLEASE continue
muhammad9t5
muhammad9t5
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yes did you understand?
Ashley99
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yes :) the other ones aren't that simple though:(
muhammad9t5
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if yes then please dont forget to click on best answer to vote me.
muhammad9t5
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thanks/.... @Ashley99
Ashley99
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no prob PLEASE keep going muhammad9t5
Ashley99
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muhammad9t5 ??????
muhammad9t5
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yes whats up?
muhammad9t5
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friend thats your answer.....
Ashley99
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can you PLEASE help me w/ the other probs too??
Ashley99
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you explain things very well :)
muhammad9t5
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yes friend i will do my best to help you more..
muhammad9t5
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friend whats your other question?
Ashley99
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click the attachment it's #2
muhammad9t5
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friend its just like we do addition 1+2=3 so its same also as below
\[\sqrt{11}+2\sqrt{11}\]
\[3\sqrt{7}\] its your answer...
muhammad9t5
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sorry \[3\sqrt{11}\]
Ashley99
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ok that's wat i thought but i doubt myself :)
Ashley99
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#3 Please (you rock)
muhammad9t5
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friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.
Ashley99
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another check i'm kinda iffy about this lesson it's
√3y^3
Ashley99
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#4 I think is-
13p^3√p-2p√p
yes or no
Ashley99
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muhammad9t5
??
muhammad9t5
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wait friend.
Ashley99
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you still there muhammad9t5 ??
muhammad9t5
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yes i am
Ashley99
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did you get the Q?
muhammad9t5
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no i didnt... but i will do it later.
Ashley99
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@Loujoelou i need your help w/
Ashley99
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PLEASE I REALLY NEED HELP NOW
Ashley99
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@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]
HELP SIMPLIFY
Loujoelou
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K I just opened the document.
Ashley99
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no not the stuff in the doc the message above!!!
Loujoelou
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Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?
Ashley99
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1st term yep
Loujoelou
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What about the 2nd?
Ashley99
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nope?
Loujoelou
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Yes, you're correct. Do you know how to simplify it?
muhammad9t5
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friend can we move to 5th??
Ashley99
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@muhammad9t5 sure
Loujoelou
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?
Ashley99
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@Loujoelou eh......... please explain
muhammad9t5
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\[\sqrt{169}-\sqrt{50}-\sqrt{8}\]
square root of redical 169 is 13 ,
square root of 50 is 5redical2 and
square root of 8 is 2redical2 therefor
\[13-5\sqrt{2}-2\sqrt{2}\]
\[13-7\sqrt{2}\] is your answer.
Loujoelou
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Factors of 8= 2*2*2.
|dw:1342281410594:dw|
That is what we would do. That would then give us \[2x \sqrt{2x}\]
Ashley99
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@muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways
Ashley99
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|dw:1342281716312:dw|
Loujoelou
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Now for the 3rd term. \[-5 \sqrt{18x}\]
Factors of 18=2*3*3
|dw:1342281717942:dw|
Ashley99
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@Loujoelou
????
Ashley99
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@muhammad9t5 PLEASE this is the last Q
Loujoelou
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\[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]
Ashley99
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oh ok
Ashley99
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ITS -5 not -15!!!!!!!!
Loujoelou
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\[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is
Ashley99
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the first 2 terms are right but the last is -15 sqrt(2x)
Loujoelou
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That's what I wrote.
Ashley99
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i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver
Loujoelou
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No prob. :)
Ashley99
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what is the final answer then?
Ashley99
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@Loujoelou PLEASE ANSWER ME THEN I"M DONE
Loujoelou
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Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.
Ashley99
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but it's 2x not just 2
Ashley99
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3+2x-15
Loujoelou
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oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.
Ashley99
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so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]
Ashley99
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????
Loujoelou
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No
Ashley99
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GREAT *sigh*
1 assignment down 16 more to go
Ashley99
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17 MORE!!!
Loujoelou
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Darn my internet connection isn't working :/ g2g sorry