## Ashley99 Group Title PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions 2 years ago 2 years ago

1. Ashley99

2. WONDEMU

could I get any Idea about computer science? I have some project work this week!!

3. Ashley99

Earth-Space Science??

4. hba

1)-7

5. hba

2)2$\sqrt{11}$

6. Ashley99

you mean 3√11 or 2√22 ????

7. hba

|dw:1342277961301:dw|

8. Ashley99

k #3 ?? :)

friend you dont count x in that just count the numbers. like below $2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7$ $3\sqrt{7}-3\sqrt{7}-7$ $-7$

11. Ashley99

yes did you understand?

13. Ashley99

yes :) the other ones aren't that simple though:(

if yes then please dont forget to click on best answer to vote me.

thanks/.... @Ashley99

16. Ashley99

17. Ashley99

yes whats up?

20. Ashley99

21. Ashley99

you explain things very well :)

24. Ashley99

click the attachment it's #2

friend its just like we do addition 1+2=3 so its same also as below $\sqrt{11}+2\sqrt{11}$ $3\sqrt{7}$ its your answer...

sorry $3\sqrt{11}$

27. Ashley99

ok that's wat i thought but i doubt myself :)

28. Ashley99

friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

30. Ashley99

31. Ashley99

#4 I think is- 13p^3√p-2p√p yes or no

32. Ashley99

wait friend.

34. Ashley99

yes i am

36. Ashley99

did you get the Q?

no i didnt... but i will do it later.

38. Ashley99

@Loujoelou i need your help w/

39. Ashley99

PLEASE I REALLY NEED HELP NOW

40. Ashley99

@Loujoelou $3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}$ HELP SIMPLIFY

41. Loujoelou

K I just opened the document.

42. Ashley99

no not the stuff in the doc the message above!!!

43. Loujoelou

Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

44. Ashley99

1st term yep

45. Loujoelou

46. Ashley99

nope?

47. Loujoelou

Yes, you're correct. Do you know how to simplify it?

friend can we move to 5th??

49. Ashley99

50. Loujoelou

?

51. Ashley99

$\sqrt{169}-\sqrt{50}-\sqrt{8}$ square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor $13-5\sqrt{2}-2\sqrt{2}$ $13-7\sqrt{2}$ is your answer.

53. Loujoelou

Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us $2x \sqrt{2x}$

54. Ashley99

@muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways

55. Ashley99

|dw:1342281716312:dw|

56. Loujoelou

Now for the 3rd term. $-5 \sqrt{18x}$ Factors of 18=2*3*3 |dw:1342281717942:dw|

57. Ashley99

@Loujoelou ????

58. Ashley99

59. Loujoelou

$3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}$

60. Ashley99

oh ok

61. Ashley99

ITS -5 not -15!!!!!!!!

62. Loujoelou

$3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}$ * this is what it is

63. Ashley99

the first 2 terms are right but the last is -15 sqrt(2x)

64. Loujoelou

That's what I wrote.

65. Ashley99

i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver

66. Loujoelou

No prob. :)

67. Ashley99

what is the final answer then?

68. Ashley99

69. Loujoelou

Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.

70. Ashley99

but it's 2x not just 2

71. Ashley99

3+2x-15

72. Loujoelou

oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.

73. Ashley99

so the answer is $-12x \sqrt{2x}+2x \sqrt{2x}$

74. Ashley99

????

75. Loujoelou

No

76. Ashley99

GREAT *sigh* 1 assignment down 16 more to go

77. Ashley99

17 MORE!!!

78. Loujoelou

Darn my internet connection isn't working :/ g2g sorry