PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

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PLEASE SOLVE AND EXPLAIN Adding and Subtracting Radical Expressions

Mathematics
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HELP please explain how :)
1 Attachment
could I get any Idea about computer science? I have some project work this week!!
Earth-Space Science??

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Other answers:

  • hba
1)-7
  • hba
2)2\[\sqrt{11}\]
you mean 3√11 or 2√22 ????
  • hba
|dw:1342277961301:dw|
k #3 ?? :)
-7 is answer
friend you dont count x in that just count the numbers. like below \[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\] \[3\sqrt{7}-3\sqrt{7}-7\] \[-7\]
awesome i got that one PLEASE continue muhammad9t5
yes did you understand?
yes :) the other ones aren't that simple though:(
if yes then please dont forget to click on best answer to vote me.
thanks/.... @Ashley99
no prob PLEASE keep going muhammad9t5
muhammad9t5 ??????
yes whats up?
friend thats your answer.....
can you PLEASE help me w/ the other probs too??
you explain things very well :)
yes friend i will do my best to help you more..
friend whats your other question?
click the attachment it's #2
friend its just like we do addition 1+2=3 so its same also as below \[\sqrt{11}+2\sqrt{11}\] \[3\sqrt{7}\] its your answer...
sorry \[3\sqrt{11}\]
ok that's wat i thought but i doubt myself :)
#3 Please (you rock)
friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.
another check i'm kinda iffy about this lesson it's √3y^3
#4 I think is- 13p^3√p-2p√p yes or no
muhammad9t5 ??
wait friend.
you still there muhammad9t5 ??
yes i am
did you get the Q?
no i didnt... but i will do it later.
@Loujoelou i need your help w/
PLEASE I REALLY NEED HELP NOW
@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\] HELP SIMPLIFY
K I just opened the document.
no not the stuff in the doc the message above!!!
Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?
1st term yep
What about the 2nd?
nope?
Yes, you're correct. Do you know how to simplify it?
friend can we move to 5th??
?
@Loujoelou eh......... please explain
\[\sqrt{169}-\sqrt{50}-\sqrt{8}\] square root of redical 169 is 13 , square root of 50 is 5redical2 and square root of 8 is 2redical2 therefor \[13-5\sqrt{2}-2\sqrt{2}\] \[13-7\sqrt{2}\] is your answer.
Factors of 8= 2*2*2. |dw:1342281410594:dw| That is what we would do. That would then give us \[2x \sqrt{2x}\]
@muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways
|dw:1342281716312:dw|
Now for the 3rd term. \[-5 \sqrt{18x}\] Factors of 18=2*3*3 |dw:1342281717942:dw|
@muhammad9t5 PLEASE this is the last Q
\[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]
oh ok
ITS -5 not -15!!!!!!!!
\[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is
the first 2 terms are right but the last is -15 sqrt(2x)
That's what I wrote.
i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver
No prob. :)
what is the final answer then?
@Loujoelou PLEASE ANSWER ME THEN I"M DONE
Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.
but it's 2x not just 2
3+2x-15
oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.
so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]
????
No
GREAT *sigh* 1 assignment down 16 more to go
17 MORE!!!
Darn my internet connection isn't working :/ g2g sorry

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