PLEASE SOLVE AND EXPLAIN
Adding and Subtracting Radical Expressions

- anonymous

PLEASE SOLVE AND EXPLAIN
Adding and Subtracting Radical Expressions

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- chestercat

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- anonymous

HELP please explain how :)

##### 1 Attachment

- anonymous

could I get any Idea about computer science? I have some project work this week!!

- anonymous

Earth-Space Science??

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## More answers

- hba

1)-7

- hba

2)2\[\sqrt{11}\]

- anonymous

you mean 3√11 or 2√22
????

- hba

|dw:1342277961301:dw|

- anonymous

k #3
??
:)

- anonymous

-7 is answer

- anonymous

friend you dont count x in that just count the numbers. like below
\[2\sqrt{7}+\sqrt{7}-3\sqrt{7}-7\]
\[3\sqrt{7}-3\sqrt{7}-7\]
\[-7\]

- anonymous

awesome i got that one PLEASE continue
muhammad9t5

- anonymous

yes did you understand?

- anonymous

yes :) the other ones aren't that simple though:(

- anonymous

if yes then please dont forget to click on best answer to vote me.

- anonymous

thanks/.... @Ashley99

- anonymous

no prob PLEASE keep going muhammad9t5

- anonymous

muhammad9t5 ??????

- anonymous

yes whats up?

- anonymous

friend thats your answer.....

- anonymous

can you PLEASE help me w/ the other probs too??

- anonymous

you explain things very well :)

- anonymous

yes friend i will do my best to help you more..

- anonymous

friend whats your other question?

- anonymous

click the attachment it's #2

- anonymous

friend its just like we do addition 1+2=3 so its same also as below
\[\sqrt{11}+2\sqrt{11}\]
\[3\sqrt{7}\] its your answer...

- anonymous

sorry \[3\sqrt{11}\]

- anonymous

ok that's wat i thought but i doubt myself :)

- anonymous

#3 Please (you rock)

- anonymous

friend i suggest you to in 3rd put y=1 then y will be removed you will get answer easily.

- anonymous

another check i'm kinda iffy about this lesson it's
√3y^3

- anonymous

#4 I think is-
13p^3√p-2p√p
yes or no

- anonymous

muhammad9t5
??

- anonymous

wait friend.

- anonymous

you still there muhammad9t5 ??

- anonymous

yes i am

- anonymous

did you get the Q?

- anonymous

no i didnt... but i will do it later.

- anonymous

@Loujoelou i need your help w/

- anonymous

PLEASE I REALLY NEED HELP NOW

- anonymous

@Loujoelou \[3\sqrt{2x}+x \sqrt{8x}-5\sqrt{18x}\]
HELP SIMPLIFY

- anonymous

K I just opened the document.

- anonymous

no not the stuff in the doc the message above!!!

- anonymous

Nvm then I'll help you with this. Okay. So tell me, is the 1st term already simplified, do you know?

- anonymous

1st term yep

- anonymous

What about the 2nd?

- anonymous

nope?

- anonymous

Yes, you're correct. Do you know how to simplify it?

- anonymous

friend can we move to 5th??

- anonymous

@muhammad9t5 sure

- anonymous

?

- anonymous

@Loujoelou eh......... please explain

- anonymous

\[\sqrt{169}-\sqrt{50}-\sqrt{8}\]
square root of redical 169 is 13 ,
square root of 50 is 5redical2 and
square root of 8 is 2redical2 therefor
\[13-5\sqrt{2}-2\sqrt{2}\]
\[13-7\sqrt{2}\] is your answer.

- anonymous

Factors of 8= 2*2*2.
|dw:1342281410594:dw|
That is what we would do. That would then give us \[2x \sqrt{2x}\]

- anonymous

@muhammad9t5 thnx that makes things alot clearer can you also help w/ the problem Lou is doing right now i types it above a little ways

- anonymous

|dw:1342281716312:dw|

- anonymous

Now for the 3rd term. \[-5 \sqrt{18x}\]
Factors of 18=2*3*3
|dw:1342281717942:dw|

- anonymous

@Loujoelou
????

- anonymous

@muhammad9t5 PLEASE this is the last Q

- anonymous

\[3 \sqrt{2x} + 2x \sqrt{2x} - 15\sqrt{2x}\]

- anonymous

oh ok

- anonymous

ITS -5 not -15!!!!!!!!

- anonymous

\[3 \sqrt{2x}+ 2 \sqrt{2x} -15 \sqrt{2x}\] * this is what it is

- anonymous

the first 2 terms are right but the last is -15 sqrt(2x)

- anonymous

That's what I wrote.

- anonymous

i can solve from there THANK YOU THANK YOU THANK YOU you are truly a lifesaver

- anonymous

No prob. :)

- anonymous

what is the final answer then?

- anonymous

@Loujoelou PLEASE ANSWER ME THEN I"M DONE

- anonymous

Since they have the same root (the 2x) all you have to do is 3+3-15 to find the number outside the square root.

- anonymous

but it's 2x not just 2

- anonymous

3+2x-15

- anonymous

oh sry forgot. :/ you leave the 2nd term like it is cause there's nothing to combine it with. You add the 1st/3rd terms together cause they are like terms.

- anonymous

so the answer is \[-12x \sqrt{2x}+2x \sqrt{2x}\]

- anonymous

????

- anonymous

No

- anonymous

GREAT *sigh*
1 assignment down 16 more to go

- anonymous

17 MORE!!!

- anonymous

Darn my internet connection isn't working :/ g2g sorry

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