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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2\((a+bi)(c+di)=(acbd)+(ad+bc)i\) either that, or multiply out using four multiplications like you would with \((x+2)(x+5)\) and then at the end replace \(i^2\) by \(1\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2here \(a=10,b=3, c=5,d=2\) so first method gives \[(10\times 53\times (2))+(10\times (2)+3\times 5)i\]

ashleyb
 2 years ago
Best ResponseYou've already chosen the best response.0sorry but im still having trouble understanding

Ajk
 2 years ago
Best ResponseYou've already chosen the best response.0I just FOILed and then combined like terms. So, 10 x 5 = 50, 10 x 2i = 20i, 3i x 5 = 15i, and 3i x 2i = 6i^2. Combining like terms gets me 50  5i 6i^2, but we then remember that i^2 = 1, so further simplifying becomes 50  5i + 6 > 56  5i. Did that make sense?
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