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kmstevens10

Simplify the expression. 12 p 5

  • one year ago
  • one year ago

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  1. mathslover
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    did u mean this : \[\large{^{12}p_5}\]

    • one year ago
  2. kmstevens10
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    the 12 was down p is up and 5 is up with 12 idk how to write it

    • one year ago
  3. mathslover
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    did u mean this ? :\[\large{^5p_{12}}\] ?

    • one year ago
  4. kmstevens10
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    \[12 p 5\] but the p is higher

    • one year ago
  5. mathslover
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    oh k : \[\large{12*5^p}\] ? can u draw that ?

    • one year ago
  6. kmstevens10
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    i dont even know how to do this

    • one year ago
  7. mathslover
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    u dont know how to draw?

    • one year ago
  8. kmstevens10
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    oh haha hold on

    • one year ago
  9. kmstevens10
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    |dw:1342318081697:dw|

    • one year ago
  10. mathslover
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    \[\large{12^p*5}\] right ?

    • one year ago
  11. kmstevens10
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    These are the options A. 11,880 B. 95,040 C. 1,235,520 D. 7,920

    • one year ago
  12. mathslover
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    what is p there ?

    • one year ago
  13. mathslover
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    is there any value given ?

    • one year ago
  14. kmstevens10
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    i am showing you what the problem is

    • one year ago
  15. mathslover
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    ok 1

    • one year ago
  16. lgbasallote
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    \[12 P 5 \implies \frac{12!}{(12-5)!}\]

    • one year ago
  17. mathslover
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    lolz @lgbasallote ...this problem is not like that.. wait for original problem

    • one year ago
  18. lgbasallote
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    \[\frac{12!}{(12-5)!} \implies \frac{12!}{7!}\] @mathslover it is...used the good ol calculator already

    • one year ago
  19. kmstevens10
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    okay i drew the problem out and wrote it, i dont know how else i can explain this all it says is simplify the expression.... and the options are A. 11,880 B. 95,040 C. 1,235,520 D. 7,920

    • one year ago
  20. mathslover
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    ok !!! 12*11*10*9*8 = 95040

    • one year ago
  21. mathslover
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    u wrote the problem wrongly i think

    • one year ago
  22. kmstevens10
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    im writing it out the way it is displayed

    • one year ago
  23. lgbasallote
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    bottomline it's permutation so use the formula i provided

    • one year ago
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