anonymous
  • anonymous
log3(5)+log3x=log3(10)
Mathematics
jamiebookeater
  • jamiebookeater
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mathslover
  • mathslover
ok so here base is same
mathslover
  • mathslover
\[\large{log_a(b)+log_a(c)=log_a(bc)}\]
mathslover
  • mathslover
can u write the given question in this form ?

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anonymous
  • anonymous
log3(5)+log3x=log3(10) => log3 (5 X 3x ) =log3(10) =>log3(15x) =log3(10) =>15x=10 =>x=2/3
mathslover
  • mathslover
i think u did a mistake some where @DHASHNI \[\large{log_3(5)+log_3(x)=log_3(5*x)}\]but it is given equal to \(\large{log_3{10}}\) \(\large{\log_3(5x)=log_3(10)}\) \(\large{5x=10}\) \(\large{x=\frac{10}{5}=2}\)
anonymous
  • anonymous
yes
mathslover
  • mathslover
got it @cypress
anonymous
  • anonymous
|dw:1342329547945:dw|
mathslover
  • mathslover
|dw:1342329722027:dw|
anonymous
  • anonymous
@mathslover : yeah ,,, thanks
mathslover
  • mathslover
.np :)
anonymous
  • anonymous
what about |dw:1342329775502:dw|
mathslover
  • mathslover
why not to try understand this ? http://www.wolframalpha.com/input/?i=2e%5Ex-5%3D1&t=crmtb01
mathslover
  • mathslover
x=log(3)
anonymous
  • anonymous
|dw:1342329851620:dw|
mathslover
  • mathslover
gr8 work @DHASHNI
anonymous
  • anonymous
:)
jiteshmeghwal9
  • jiteshmeghwal9
Use the property\[\LARGE{\log_{n}{a}+\log_{n}{b}=\log_{n}{a+b}} \]

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