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cypress
 3 years ago
log3(5)+log3x=log3(10)
cypress
 3 years ago
log3(5)+log3x=log3(10)

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mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2ok so here base is same

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2\[\large{log_a(b)+log_a(c)=log_a(bc)}\]

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2can u write the given question in this form ?

DHASHNI
 3 years ago
Best ResponseYou've already chosen the best response.1log3(5)+log3x=log3(10) => log3 (5 X 3x ) =log3(10) =>log3(15x) =log3(10) =>15x=10 =>x=2/3

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2i think u did a mistake some where @DHASHNI \[\large{log_3(5)+log_3(x)=log_3(5*x)}\]but it is given equal to \(\large{log_3{10}}\) \(\large{\log_3(5x)=log_3(10)}\) \(\large{5x=10}\) \(\large{x=\frac{10}{5}=2}\)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1342329722027:dw

DHASHNI
 3 years ago
Best ResponseYou've already chosen the best response.1@mathslover : yeah ,,, thanks

cypress
 3 years ago
Best ResponseYou've already chosen the best response.0what about dw:1342329775502:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.2why not to try understand this ? http://www.wolframalpha.com/input/?i=2e%5Ex5%3D1&t=crmtb01

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.0Use the property\[\LARGE{\log_{n}{a}+\log_{n}{b}=\log_{n}{a+b}} \]
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