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cypress

  • 2 years ago

log3(5)+log3x=log3(10)

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  1. mathslover
    • 2 years ago
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    ok so here base is same

  2. mathslover
    • 2 years ago
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    \[\large{log_a(b)+log_a(c)=log_a(bc)}\]

  3. mathslover
    • 2 years ago
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    can u write the given question in this form ?

  4. DHASHNI
    • 2 years ago
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    log3(5)+log3x=log3(10) => log3 (5 X 3x ) =log3(10) =>log3(15x) =log3(10) =>15x=10 =>x=2/3

  5. mathslover
    • 2 years ago
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    i think u did a mistake some where @DHASHNI \[\large{log_3(5)+log_3(x)=log_3(5*x)}\]but it is given equal to \(\large{log_3{10}}\) \(\large{\log_3(5x)=log_3(10)}\) \(\large{5x=10}\) \(\large{x=\frac{10}{5}=2}\)

  6. cypress
    • 2 years ago
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    yes

  7. mathslover
    • 2 years ago
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    got it @cypress

  8. cypress
    • 2 years ago
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    |dw:1342329547945:dw|

  9. mathslover
    • 2 years ago
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    |dw:1342329722027:dw|

  10. DHASHNI
    • 2 years ago
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    @mathslover : yeah ,,, thanks

  11. mathslover
    • 2 years ago
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    .np :)

  12. cypress
    • 2 years ago
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    what about |dw:1342329775502:dw|

  13. mathslover
    • 2 years ago
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    why not to try understand this ? http://www.wolframalpha.com/input/?i=2e%5Ex-5%3D1&t=crmtb01

  14. mathslover
    • 2 years ago
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    x=log(3)

  15. DHASHNI
    • 2 years ago
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    |dw:1342329851620:dw|

  16. mathslover
    • 2 years ago
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    gr8 work @DHASHNI

  17. DHASHNI
    • 2 years ago
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    :)

  18. jiteshmeghwal9
    • 2 years ago
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    Use the property\[\LARGE{\log_{n}{a}+\log_{n}{b}=\log_{n}{a+b}} \]

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