A community for students.
Here's the question you clicked on:
 0 viewing
HillDP
 2 years ago
y^2=2a^3x/x^2+a^2 implicit differentiation
HillDP
 2 years ago
y^2=2a^3x/x^2+a^2 implicit differentiation

This Question is Closed

HillDP
 2 years ago
Best ResponseYou've already chosen the best response.0i didnt get the right answer. ive tried to solve it.

HillDP
 2 years ago
Best ResponseYou've already chosen the best response.0thats the right equation, help me get the answer. thanks.

DHASHNI
 2 years ago
Best ResponseYou've already chosen the best response.2d/dx(y^2) = d/dx((2 a^3 x)/(a^2+x^2)) The derivative of y^2 is zero: = 0 = d/dx((2 a^3 x)/(a^2+x^2)) Factor out constants: = 0 = 2 (d/dx((a^3 x)/(a^2+x^2))) Factor out constants: = 0 = 2 (a^3 (d/dx(x/(a^2+x^2)))) Use the quotient rule, d/dx(u/v) = (v ( du)/( dx)u ( dv)/( dx))/v^2, where u = x and v = a^2+x^2: = 0 = 2 a^3 ((a^2+x^2) (d/dx(x))x (d/dx(a^2+x^2)))/(a^2+x^2)^2 The derivative of x is 1: = 0 = (2 a^3 (x (d/dx(a^2+x^2))+a^2+x^2))/(a^2+x^2)^2 Differentiate the sum term by term: = 0 = (2 a^3 (x (d/dx(a^2)+d/dx(x^2))+a^2+x^2))/(a^2+x^2)^2 The derivative of a^2 is zero: = 0 = (2 a^3 (x (d/dx(x^2)+0)+a^2+x^2))/(a^2+x^2)^2 The derivative of x^2 is 2 x: = 0 = (2 a^3 (a^2+x^2x (2 x)))/(a^2+x^2)^2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.