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HillDPBest ResponseYou've already chosen the best response.0
i didnt get the right answer. ive tried to solve it.
 one year ago

HillDPBest ResponseYou've already chosen the best response.0
thats the right equation, help me get the answer. thanks.
 one year ago

DHASHNIBest ResponseYou've already chosen the best response.2
d/dx(y^2) = d/dx((2 a^3 x)/(a^2+x^2)) The derivative of y^2 is zero: = 0 = d/dx((2 a^3 x)/(a^2+x^2)) Factor out constants: = 0 = 2 (d/dx((a^3 x)/(a^2+x^2))) Factor out constants: = 0 = 2 (a^3 (d/dx(x/(a^2+x^2)))) Use the quotient rule, d/dx(u/v) = (v ( du)/( dx)u ( dv)/( dx))/v^2, where u = x and v = a^2+x^2: = 0 = 2 a^3 ((a^2+x^2) (d/dx(x))x (d/dx(a^2+x^2)))/(a^2+x^2)^2 The derivative of x is 1: = 0 = (2 a^3 (x (d/dx(a^2+x^2))+a^2+x^2))/(a^2+x^2)^2 Differentiate the sum term by term: = 0 = (2 a^3 (x (d/dx(a^2)+d/dx(x^2))+a^2+x^2))/(a^2+x^2)^2 The derivative of a^2 is zero: = 0 = (2 a^3 (x (d/dx(x^2)+0)+a^2+x^2))/(a^2+x^2)^2 The derivative of x^2 is 2 x: = 0 = (2 a^3 (a^2+x^2x (2 x)))/(a^2+x^2)^2
 one year ago
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