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Master.RohanChakraborty

  • 3 years ago

\[ Using \ factor \ theorem,\ prove \ that \a + b, \ b + c \ and \ c + a \ are \ the \\ factors \ of \ (a+b+c)^3 - (a^3 + b^3 + c^3)\] 2. If f(x) = x4 - 2x3 + 3x2 - ax + b is a polynomial such that when it is divided by x - 1 and x + 1, the remainder are 5 and 19 respectively. Determine the remainder when f(x) is divided by x - 2.

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  1. Master.RohanChakraborty
    • 3 years ago
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    @lgbasallote @Rohangrr @Ruchi. @FoolAroundMath

  2. Master.RohanChakraborty
    • 3 years ago
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    Please help

  3. Master.RohanChakraborty
    • 3 years ago
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    @nbouscal @No-data Plzzz help

  4. Master.RohanChakraborty
    • 3 years ago
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    @Hero

  5. Master.RohanChakraborty
    • 3 years ago
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    @hamza_b23

  6. Master.RohanChakraborty
    • 3 years ago
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    please help

  7. Ruchi.
    • 3 years ago
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    sorry maths is nt my subject.

  8. Master.RohanChakraborty
    • 3 years ago
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    @Hero can u help

  9. Hero
    • 3 years ago
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    Maybe

  10. Master.RohanChakraborty
    • 3 years ago
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    plzz

  11. Hero
    • 3 years ago
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    Give me 20 minutes

  12. Master.RohanChakraborty
    • 3 years ago
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    Order passed

  13. Master.RohanChakraborty
    • 3 years ago
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    \[ Using \ factor \ theorem,\ prove \ that \ a + b, \ b + c \ and \ c + a \ are \ the \\ factors \ of \ (a+b+c)^3 - (a^3 + b^3 + c^3)\]

  14. Master.RohanChakraborty
    • 3 years ago
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    Perfect Question @Hero 15 mins left

  15. Master.RohanChakraborty
    • 3 years ago
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    @lgbasallote can u please help

  16. Hero
    • 3 years ago
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    By the way, what are you the master of?

  17. A.Avinash_Goutham
    • 3 years ago
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    consider it to be a function of a....say f(a) and now if a+b i s a factor f(-b) =0

  18. mukushla
    • 3 years ago
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    for second part of problem: f(x) is divided by x - 1 the remainder is 5 -----> f(1)=5 (I) f(x) is divided by x + 1 the remainder is 19 -----> f(-1)=19 (II) equations (I) and (II) will give u the unknowns a and b now if f(x) is divided by x - 2 the remainder is f(2)

  19. mukushla
    • 3 years ago
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    first part of question : i go with @A.Avinash_Goutham

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