Here's the question you clicked on:
iceywheniplease7
Solve 1 divided by the product of 2 times a squared equals 1 divided by a minus one-half
|dw:1342334134925:dw| but this is not solvable
let the no.be x then\[\frac {1}{2x^{2}}=\frac {1}{-1/2}\] \[\frac {1}{2x^{2}}=\frac {-2}{1}\] cross multiplying \[\ {1}=\ {-2(2x^{2})}\] \[\ {1}=\ {-4x^{2}}\] \[\ {4x^{2}+1}=\ {0}\] \[\ {x^{2}}=\frac {-1}{4}\] \[\ {x}=\frac {i}{2}\]
yeah we can use imaginary roots !!!! ?(y)