Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Whom of you can explain it to me? http://jeremykun.files.wordpress.com/2011/06/triangle-proof.png

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

http://mathoverflow.net/questions/8846/proofs-without-words/69756#69756
If it's fairly easy and you think I am not pushing myself please do tell me, instead of giving out the answer.
BTW: Nice site.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

@Ishaan94 - do you know how to get the sum of all the components in the last triangle?
No ._.
wait
Is it like this? (2n+1)+2(2n+1)+3(2n+1)+...+n(2n+1)
exactly - now factor out the (2n+1)
i think like this way: i will assume that this is true until line n+1 (go downward from first line), i have: first line is true, 1+n+n = 2n + 1. so with line: n+1 we have: (n+1) + ... (n+1) at first triangle, at second triangle, we have: 1+ 2 + ... + n+ n+1, and at third: n+1 + n + ... + 1, sum last line, we still get: 2(n+1) + 1 + .... 2(n+1) + 1
\[\frac{n\left(n+1\right) \left(2n+1\right)}2\]What about the six?
that is correct - now you have to subtract the sum of the previous 2 triangles from this
but why?
what you are trying to find is the sum of the numbers in the 1st triangle
\[1^1+2^2+3^3+...\]
that should have started with \(1^2\)
it is a visual proof of this sum
oh I see it
It's an interesting proof - I suggest you try and do it yourself - you'll have greater pleasure from that :)
thanks, i will try my best.
let me know if you require a clue.
when you do "see" how to do it - it is quite remarkable!
@Ishaan94 - try turning your head as you view the triangles on the left...
this really is a "visual" solution - so don't think about any complex math here
OMG this is the best proof I have seen in my life so far
:) glad you "saw" it at last!
it is a very pleasing proof
it is. and thanks a lot asnaseer. :-)
yw :)
really beautiful xD

Not the answer you are looking for?

Search for more explanations.

Ask your own question