A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

Let V be the set of all continuous functions defined on [0,1]. Explain why V is a subspace of T(R). Let W be the subset of V defined by W = {f E V: ∫(0 to 1) (f(t)dt = 0)}. Show that W is a subspace of V. For the first part, it looks like I need to show: 1) zero vector of T(R) is in V 2) when u and v belong to V, u + v belongs to V 3) when u belongs to V and c is scalar, cu belongs to V How would I show that the zero function lies in V? Is it V(0) = 0? I'm not sure what to do next.

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So there are two things that need to be proven here. First, that V is a subspace of T(R) and second that W is a subspace of V. I will show you both below. 1) To prove V is a subspace of T(R), first we need to show that V contains the zero vector. Meaning that for its interval of domain ( D=[0,1]), one of the continuous functions equals zero. And thats easy to show because V contains all continuous functions in that domain D. So just pick a function, maybe f(x)= x, and then we see that f(0)=0. Thats a zero thats contained in V. Next we need to show that the sum of two vectors contained in V are in V and that the product of a scalar k in T(R) and a continuous function in V is in V. Well by definition of continuous functions- the sum of two continuous functions is continuous and the product of a constant with a continuous function is also continuous ( http://www.jtaylor1142001.net/calcjat/DEFINITN/ContRules.html). This finishes part 1. 2) I'm not sure if you needed help with this part, but the same rules apply. The sum of the integrals of two functions is just the integral of those two functions, which is just the integral of another function. And the product of a constant k in T(R) and the integral of a function is just another integral of a function- so there goes that. Oh, and I believe for the zero vector, W already contains it because ∫(0 to 1) (f(t)dt = 0. Ask if you have any more questions.

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks, that makes sense

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.