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this involves both the chain rule and the quotient rule

or you can use log laws to change it first; then diferentiate it, would be easier.

@failmathmajor only the 2/x^3 is a fraction

is it
\[\log\left(5x^{4}-\frac{2}{x^{3}}\right) ?\]

that would be much easier

so using log properties you can say that \[\log_{10} {x} = \ln x / \ln 10 \]

ln10 is a constant, you can factor that out

can you use the chain rule fluently?

y'=pu(x) * u'(x) right?

d(f(g(x))/dx = (dg(x)/dx)*(df(g(x))/dx) is the way I know it

that may look confusing now that I see it

don't need the quotient in this case:
can treat /x^3 as a x^-3

and you would still need the chain rule for that anyway

but enough arguing

Did an argument started? lol

\[(d(\ln (5x^4 - 2x^{-3}))/dx )/ \ln10\]
is what it simplifies down to, to be concise

\[2/x^3= 2 * x^{-3}\]

\[\frac{\frac{d(\ln(5x^4−2x^{−3}))}{dx}}{\ln10}\]

@catamountz15
what?

I am almost entirely sure that that isn't a form of the answer.

Here are the steps in to solving this problem.

that isn't what you wrote though

My apologies that was an answer to a different problem.