Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

MrMooseBest ResponseYou've already chosen the best response.0
this involves both the chain rule and the quotient rule
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
or you can use log laws to change it first; then diferentiate it, would be easier.
 one year ago

cunninncBest ResponseYou've already chosen the best response.0
@failmathmajor only the 2/x^3 is a fraction
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
is it \[\log\left(5x^{4}\frac{2}{x^{3}}\right) ?\]
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
that would be much easier
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
so using log properties you can say that \[\log_{10} {x} = \ln x / \ln 10 \]
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
ln10 is a constant, you can factor that out
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
can you use the chain rule fluently?
 one year ago

cunninncBest ResponseYou've already chosen the best response.0
y'=pu(x) * u'(x) right?
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
d(f(g(x))/dx = (dg(x)/dx)*(df(g(x))/dx) is the way I know it
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Or..\[y= \log\left(5x^{4}\frac{2}{x^{3}}\right) y = \log\left(\frac{5x^{7}2}{x^{3}}\right) => y = \log\left(5x^{7}2\right)  \log(x^3)\] Might be easier; than the quotient role and chain rule..
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
that may look confusing now that I see it
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
don't need the quotient in this case: can treat /x^3 as a x^3
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
@cunninnc: are you able to do it now?
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
and you would still need the chain rule for that anyway
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Did an argument started? lol
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
\[(d(\ln (5x^4  2x^{3}))/dx )/ \ln10\] is what it simplifies down to, to be concise
 one year ago

cunninncBest ResponseYou've already chosen the best response.0
@Mimi_x3 kinda .... i see mr. moose got 2x^3 where does ^3 come froms
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Sorry i don't know what MrMoose is doing. @MrMoose: Use \frac{x}{y} for fractions :)
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
Or why not try the method that i used :) \[ \frac{d}{dx} \log\left(5x^{7}2\right) \frac{d}{dx} \log(x^3)\]
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
when you divide you subtract exponents, so that is equivalent to saying \[2 * \frac{x^0}{x^3}\] then subtract exponents in division
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
\[\frac{\frac{d(\ln(5x^4−2x^{−3}))}{dx}}{\ln10}\]
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
I am almost entirely sure that that isn't a form of the answer.
 one year ago

catamountz15Best ResponseYou've already chosen the best response.0
Here are the steps in to solving this problem.
 one year ago

MrMooseBest ResponseYou've already chosen the best response.0
that isn't what you wrote though
 one year ago

catamountz15Best ResponseYou've already chosen the best response.0
My apologies that was an answer to a different problem.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.