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Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1\[\text{Is this the question?}\frac3{x + 1} + \frac{2}{x + 3} = 2\]

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac3{x + 1} + \frac{2}{x + 3} = 2\]\[\frac{3}{x + 1} \times \frac{x + 3}{x + 3} + \frac{2}{x + 3} \times \frac{x + 1}{x + 1} = \frac{2}{1} \times \frac{(x + 1)(x + 3)}{(x + 1)(x + 3)}\]\[\frac{3(x + 3) + 2(x + 1)}{x^{2} + 4x + 3} = \frac{ 2(x^{2} + 4x + 3)}{x^{2} + 4x + 3}\]You can just drop the denominator now. \[3(x + 3) + 2(x + 1) = 2(x^{2} + 4x + 3)\]Can you solve it now?

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1Did you get it yet?

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0the next step please?

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1\[3x + 9 + 2x + 2 = 2x^{2} + 8x + 6\]\[2x^{2} + 3x  5 = 0\]

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1Can you solve the quadratic?

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0i'm still doing it.

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0\[3\pm i \sqrt{31} \over 4\] is that right?

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1No. \[3x + 9 + 2x + 2 = 2x^{2} + 8x + 6\]\[2x^{2} + 3x  5 = 0\]\[2x^{2} 2x + 5x  5 = 0\]\[2x(x  1) + 5(x  1) = 0\]\[(2x + 5)(x  1) = 0\]\[x = \frac{5}{2}, 1\]

Calcmathlete
 2 years ago
Best ResponseYou've already chosen the best response.1Do you see how I got that?

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0thank you for your help.
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