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how do you solve 3/x+1 +2/x+3 =2? Please show me step by step. Thank you.
 one year ago
 one year ago
how do you solve 3/x+1 +2/x+3 =2? Please show me step by step. Thank you.
 one year ago
 one year ago

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CalcmathleteBest ResponseYou've already chosen the best response.1
\[\text{Is this the question?}\frac3{x + 1} + \frac{2}{x + 3} = 2\]
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
\[\frac3{x + 1} + \frac{2}{x + 3} = 2\]\[\frac{3}{x + 1} \times \frac{x + 3}{x + 3} + \frac{2}{x + 3} \times \frac{x + 1}{x + 1} = \frac{2}{1} \times \frac{(x + 1)(x + 3)}{(x + 1)(x + 3)}\]\[\frac{3(x + 3) + 2(x + 1)}{x^{2} + 4x + 3} = \frac{ 2(x^{2} + 4x + 3)}{x^{2} + 4x + 3}\]You can just drop the denominator now. \[3(x + 3) + 2(x + 1) = 2(x^{2} + 4x + 3)\]Can you solve it now?
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
Did you get it yet?
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
the next step please?
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
\[3x + 9 + 2x + 2 = 2x^{2} + 8x + 6\]\[2x^{2} + 3x  5 = 0\]
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
Can you solve the quadratic?
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
What did you get?
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
i'm still doing it.
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
\[3\pm i \sqrt{31} \over 4\] is that right?
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
No. \[3x + 9 + 2x + 2 = 2x^{2} + 8x + 6\]\[2x^{2} + 3x  5 = 0\]\[2x^{2} 2x + 5x  5 = 0\]\[2x(x  1) + 5(x  1) = 0\]\[(2x + 5)(x  1) = 0\]\[x = \frac{5}{2}, 1\]
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.1
Do you see how I got that?
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
thank you for your help.
 one year ago
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