Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

shayanreloadedBest ResponseYou've already chosen the best response.0
Accelerationtime graph dw:1342512372407:dw Velocity time graph dw:1342512427429:dw Now about the position time graph
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
dw:1342512503350:dw which curves(of the 3) will be steeper?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
ace increases from origin to t1 constant from t1 to t2 and decreases from t2 onward. but ace is max from t1 to t2. I hope im understandable
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
ok, so u want to know how will the positiontime graph look like?
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
I'm not sure, but maybe it looks like this: dw:1342513483775:dw correct me if i'm wrong.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
dw:1342513648649:dw ace remains positive always
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
yea, i was going to type in that right now. the max point should not be reached. since V is not 0 anywhere.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
the graph should be steeper from origin to t1 than in the interval t1  t2.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
@Ishaan94 the velocity is NOT constant from t1 to t2. accel is.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
velocity is NEVER constant
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
dw:1342513895634:dw The graph should look somewhat like this I want to know the order of their steepness.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
i think the graph should be of this form: dw:1342513986456:dw
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
1 will be more steep than 2.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
the ace is always positive so the velocity always increases and so the slope of xt graph always increases
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
sry my bad! i saw the slop of accel!
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
ace decreases t2 onward but stays positive notice
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
i think the order of steepness should be 1 > 2 > 3. i'm just using logic here: accel is increasing from 0 to t1 hence vel is increasing at the fastest rate in this interval. from t1 to t2, accel is constant. so vel is increasing at a constant rate ( this rate < the rate from 0 to t1). and from t2 to the end, accel is decreasing. so the vel is anyway decreasing. so less distance will be covered as compared to the former 2 intervals.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
the rate of increase of velocity is max from t1 to t2 because ace is max(constant)
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
and from t2 the velocity increases but at a decreasing rate
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
@Ishaan94 you lost me
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
even after t2 ace is positive so slope cant be curving down right?
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
i think it should be curving down. because now the distance covered per unit time is decreasing. so 3 should be the least steep of all.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
but if ace is positive xt curve never curves down
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
right now, the interval we're considering is this: dw:1342514762867:dw so at some point the graph will curve downwards, but we don't have that within our interval.
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
dw:1342514919696:dw
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
but that works only for constant ace part what about the rest?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
and i just want the order @Ishaan94
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
@Ishaan94 yea, i think we can leave the precision out for this sum. just an approximation ill suffice.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
okay, here's my final guess: 2 > 1 > 3.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
or should it be 2 > 1 = 3 ?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
Lets keep the question open for more opinions
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
tell me this: accel is increasing and decreasing at the same rate from 0 to t1 and from t2 to the end. so what happens to the distance covered per unit time during these intervals? will the be equal?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
I am sorry for deleting my previous posts. Acceleration is positive from t2 and on wards but I presumed it to be negative :( My latest attempt. I know it sucks but still
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Oops wrong curve, from t1 to t2, it should be dw:1342517034897:dwA parabola.
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
so the answer is 2 > 1 > 3 right?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
I am sorry. I can't be sure from what it seems my graph from t2 can't be right. VelocityTime graph form t2 is downward parabola right? a = dv/dt?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Darwin... this is so embarrassing :(
 one year ago

Vaidehi09Best ResponseYou've already chosen the best response.1
it tends to go downwards. but doesn't do so completely.
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
so my graph from t2 isn't right either
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
i hope my math is right
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
mukushla just to be sure of my answer. can you draw an approximate graph? please.
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.3
Velocitytime is: dw:1342520614050:dw with 2 halfparabolas between 0 and t1 and between 0 t2 and tfinal
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.3
Displacementtime is: dw:1342520737774:dw The curve is always increasing as well as increasing in slope. Only the curvature becomes 0 at the end (would go on in a straight line if acceleration remains 0 or would reach an inflexion point if acceleration becomes negative after tfinal
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
Seems like I made a fool of myself. But Vincent, slope isn't always increasing. It's constant from \(t_1\) to \(t_2\).
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
And it's decreasing from \(t_2\). Correct me if I am wrong. :
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.3
@Ishaan what you say is true of velocity, but wrong about displacement
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
I know :/ I got confused :/
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
so whats the order of steepness?? 3>2>1 ? or 1=2<3 ? does it depend on ace magnitude or rate of change of ace??
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.3
The steepness (of displacement curve) is ever increasing because velocity is; so 3>2>1 But, as velocity is a continuous function, the 3 parts of the curve will smoothly link together, without any angle at t1 and t2
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.