Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

|dw:1342512503350:dw|
which curves(of the 3) will be steeper?

ok, so u want to know how will the position-time graph look like?

yeah

I'm not sure, but maybe it looks like this:
|dw:1342513483775:dw|
correct me if i'm wrong.

|dw:1342513648649:dw|
ace remains positive always

the graph should be steeper from origin to t1 than in the interval t1 - t2.

*t1 to t2

velocity is NEVER constant

i think the graph should be of this form:
|dw:1342513986456:dw|

1 will be more steep than 2.

sry my bad! i saw the slop of accel!

ace decreases t2 onward but stays positive
notice

the rate of increase of velocity is max from t1 to t2 because ace is max(constant)

and from t2 the velocity increases but at a decreasing rate

even after t2 ace is positive so slope cant be curving down right?

but if ace is positive xt curve never curves down

|dw:1342514919696:dw|

but that works only for constant ace part what about the rest?

okay, here's my final guess:
2 > 1 > 3.

or should it be 2 > 1 = 3 ?

guess?

*answer!

Lets keep the question open for more opinions

I am sorry for deleting my previous posts. Acceleration is positive from t2 and on wards but I presumed it to be negative :(
My latest attempt. I know it sucks but still

Oops wrong curve, from t1 to t2, it should be |dw:1342517034897:dw|A parabola.

so the answer is 2 > 1 > 3 right?

Darwin... this is so embarrassing :(

it tends to go downwards. but doesn't do so completely.

so my graph from t2 isn't right either

i hope my math is right

mukushla just to be sure of my answer. can you draw an approximate graph? please.

And it's decreasing from \(t_2\). Correct me if I am wrong. :|

Oh silly me :(

Please Ignore me :(

@Ishaan what you say is true of velocity, but wrong about displacement

I know :/ I got confused :/

Thanks