Loujoelou
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable y is eliminated in the first and second equations, then the second and third equations.
3x – y + 3z = 1
4x + y – 6z = 3
4x – 2y + 3z = –3
7x – 3z = 4
12x – 9z = 3
7x – 3z = 4
4x – 6z = 3
3x + 3z = 1
12x – 9z = 3
3x + 3z = 1
4x – 6z = 3
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ParthKohli
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I prefer a question at a time. I'd help you with the first.
ParthKohli
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Add all equations.
Loujoelou
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Lol it is a question, 9ut the last 8 sets are choices.
Loujoelou
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4 sets*
ParthKohli
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lol
waterineyes
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Ha ha ha..
ParthKohli
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Start by adding the top two equations.
waterineyes
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What do you get?? @Loujoelou
Loujoelou
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I know it's either C/D, cause 3x+3z=1 is what you get when you eliminate y from 1st/2nd equation.
Loujoelou
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nvm other way around. It's A/B
Loujoelou
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Cause you get 7x-3z=4 not what I said earlier.
ParthKohli
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Yep.
ParthKohli
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Now, you multiply the second equation by 2 and then add equation 1 and 2.
waterineyes
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Now multiply second equation by 2 and then add second and third equation and let us see what you get.
Loujoelou
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K I get it now :) It's A cause you get 12x-9z=3. Was just a little confused about it.
ParthKohli
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Yep! :)
Loujoelou
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tyvm @waterineyes @ParthKohli I understand it perfectly now :) At least doing this by elimination method I mean.
ParthKohli
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You got the thing successfully. Congratulations, Lou!
waterineyes
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You are doing this by elimination only @Loujoelou
Loujoelou
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Lol thx @ParthKohli and yes for this problem I had to @waterineyes
waterineyes
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Okay..