## Loujoelou 3 years ago If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable y is eliminated in the first and second equations, then the second and third equations. 3x – y + 3z = 1 4x + y – 6z = 3 4x – 2y + 3z = –3 7x – 3z = 4 12x – 9z = 3 7x – 3z = 4 4x – 6z = 3 3x + 3z = 1 12x – 9z = 3 3x + 3z = 1 4x – 6z = 3

1. ParthKohli

I prefer a question at a time. I'd help you with the first.

2. ParthKohli

3. Loujoelou

Lol it is a question, 9ut the last 8 sets are choices.

4. Loujoelou

4 sets*

5. ParthKohli

lol

6. waterineyes

Ha ha ha..

7. ParthKohli

Start by adding the top two equations.

8. waterineyes

What do you get?? @Loujoelou

9. Loujoelou

I know it's either C/D, cause 3x+3z=1 is what you get when you eliminate y from 1st/2nd equation.

10. Loujoelou

nvm other way around. It's A/B

11. Loujoelou

Cause you get 7x-3z=4 not what I said earlier.

12. ParthKohli

Yep.

13. ParthKohli

Now, you multiply the second equation by 2 and then add equation 1 and 2.

14. waterineyes

Now multiply second equation by 2 and then add second and third equation and let us see what you get.

15. Loujoelou

K I get it now :) It's A cause you get 12x-9z=3. Was just a little confused about it.

16. ParthKohli

Yep! :)

17. Loujoelou

tyvm @waterineyes @ParthKohli I understand it perfectly now :) At least doing this by elimination method I mean.

18. ParthKohli

You got the thing successfully. Congratulations, Lou!

19. waterineyes

You are doing this by elimination only @Loujoelou

20. Loujoelou

Lol thx @ParthKohli and yes for this problem I had to @waterineyes

21. waterineyes

Okay..