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Australopithecus

A bag of cement of weight 375 N hangs from three wires as suggested in Figure P5.24. Two of the wires make angles q1 = 55.0° and q2 = 31.0° with the horizontal. If the system is in equilibrium, find the tensions T1, T2, and T3 in the wires. can someone show me how to solve this problem?

  • one year ago
  • one year ago

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  1. Australopithecus
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    • one year ago
  2. Australopithecus
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    It says the answer is: T1 = 322 N, T2 = 216 N, T3 = 375 N but why

    • one year ago
  3. edr1c
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    the mass is in equilibrium, so the net force on the mass is zero. so your T3 will be equal to mg, given in question = 375N

    • one year ago
  4. edr1c
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    the knot or the point where the 3 wires meet is also in equilibrium, so the summation of force in the horizontal direction will be equal to zero, and also applies for the same for the force in the vertical direction, \[\sum_{}^{}F _{X}=0\]\[\sum_{}^{}F _{Y}=0\]

    • one year ago
  5. edr1c
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    so after deriving the horizontal and vertical components you will be able to find the tension on the other 2 wires

    • one year ago
  6. Australopithecus
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    how do I do that?

    • one year ago
  7. edr1c
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    |dw:1342549591897:dw| 1 of the horizontal components

    • one year ago
  8. edr1c
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    bear in mind that the horizontal component for the tension made by the wire with angle 55 deg is in the opposite direction and will be a negative value. after obtaining the horizontal component equation with 2 unknowns T1 and T2, solve simultaneously with the vertical component.

    • one year ago
  9. Australopithecus
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    Not to be an ingrate but can you please just show me how to solve this?

    • one year ago
  10. edr1c
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    |dw:1342550687656:dw| substitute T2 into Fy

    • one year ago
  11. Australopithecus
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    oh I see you use system of equations

    • one year ago
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