If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the second equation. 3x – 5y + z = 12 x + 6y – z = –4 2x – 5y – 2z = –8 A) 4x + y = 8 –17y = 0 B) 2x – 11y = 16 4x + 7y = –16 C) –23y + 4z = 24 –17y = 0 D) 13y – 2z = 24 7y – 4z = 0

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What do you get if you find x in second equation??

I get x=-6y+z-4

Now plug this value in first and third equation separately and tell me what you got..

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