A community for students.
Here's the question you clicked on:
 0 viewing
kitsune0724
 2 years ago
6t^2+23t4=0 how do you solve this problem?
kitsune0724
 2 years ago
6t^2+23t4=0 how do you solve this problem?

This Question is Closed

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0I'm using the ac method

huneya
 2 years ago
Best ResponseYou've already chosen the best response.0what do u want to solve for

gitahimart
 2 years ago
Best ResponseYou've already chosen the best response.16t^2 + 23t  4 =0 product of the two roots = 6x 4 = 24 sum of two roots = 23 am thinking of 24 and 1 6t^2 + 23t  4 =0 breaking the middle term 6t^2 +24t  t  4 = 0 factoring 6t (t+4) 1( t+4) = 0 (6t1) (t+4) =0 therefore: 6t1 = 0 and t = 1/6 or t+4 = 0 and t =4 solution for t = (1/6, 4)

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0I'm sorry I'm little confused how did you get your answer?

kitsune0724
 2 years ago
Best ResponseYou've already chosen the best response.0Never I see how you got it.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.