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kitsune0724

  • 3 years ago

6t^2+23t-4=0 how do you solve this problem?

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  1. kitsune0724
    • 3 years ago
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    I'm using the ac method

  2. huneya
    • 3 years ago
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    what do u want to solve for

  3. gitahimart
    • 3 years ago
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    6t^2 + 23t - 4 =0 product of the two roots = 6x -4 = -24 sum of two roots = 23 am thinking of 24 and -1 6t^2 + 23t - 4 =0 breaking the middle term 6t^2 +24t - t - 4 = 0 factoring 6t (t+4) -1( t+4) = 0 (6t-1) (t+4) =0 therefore: 6t-1 = 0 and t = 1/6 or t+4 = 0 and t =-4 solution for t = (1/6, -4)

  4. kitsune0724
    • 3 years ago
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    I'm sorry I'm little confused how did you get your answer?

  5. kitsune0724
    • 3 years ago
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    Never I see how you got it.

  6. kitsune0724
    • 3 years ago
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    *mind

  7. gitahimart
    • 3 years ago
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    good

  8. kitsune0724
    • 3 years ago
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    Thank you.

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