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6t^2+23t-4=0 how do you solve this problem?

Mathematics
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I'm using the ac method
what do u want to solve for
6t^2 + 23t - 4 =0 product of the two roots = 6x -4 = -24 sum of two roots = 23 am thinking of 24 and -1 6t^2 + 23t - 4 =0 breaking the middle term 6t^2 +24t - t - 4 = 0 factoring 6t (t+4) -1( t+4) = 0 (6t-1) (t+4) =0 therefore: 6t-1 = 0 and t = 1/6 or t+4 = 0 and t =-4 solution for t = (1/6, -4)

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I'm sorry I'm little confused how did you get your answer?
Never I see how you got it.
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good
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