How would you evaluate this?
\[\large \sum_{n=3}^{\infty} \frac{4}{n^2-1}\]
o_O I'm thinking there's some trick here I'm not seeing...

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\[\sum_{n=3}^{\infty} \frac{-2}{n+1} + \sum_{n=3}^{\infty} \frac{2}{n-1}\]

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