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waheguru

  • 2 years ago

How Do I solve this

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  1. waheguru
    • 2 years ago
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  2. freckles
    • 2 years ago
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    What do you mean without canceling out?

  3. waheguru
    • 2 years ago
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    Can you show how to solve this

  4. freckles
    • 2 years ago
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    I'm not really sure what that means here? You mean without clearing the denominators?

  5. estudier
    • 2 years ago
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    get the number on one side of the = and the others on the other side so that you can manipulate them directly.

  6. freckles
    • 2 years ago
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    I would first clear the denominators by multiplying both sides by (x-7)

  7. waheguru
    • 2 years ago
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    CAn you show me please I tried many times

  8. freckles
    • 2 years ago
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    Multiply the 2 terms on the left by (x-7) And Multiply the 1 term on the right by (x-7)

  9. freckles
    • 2 years ago
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    What do you get after performing this?

  10. estudier
    • 2 years ago
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    No, no........

  11. freckles
    • 2 years ago
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    What @estudier ?

  12. waheguru
    • 2 years ago
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    x^2-7x+6x-42=7x-49 right?

  13. waheguru
    • 2 years ago
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    \[x^2-7x+6x-42=7x-49 \]

  14. freckles
    • 2 years ago
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    Where does that x^2 come from?

  15. estudier
    • 2 years ago
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    |dw:1342565026387:dw|

  16. waheguru
    • 2 years ago
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    Freckles when I timed x(x-7)

  17. freckles
    • 2 years ago
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    What is \[\frac{x}{x-7} \cdot (x-7)=?\] \[6 \cdot (x-7)=?\] \[\frac{7}{x-7} \cdot (x-7)=?\]

  18. estudier
    • 2 years ago
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    This equation is inconsistent.

  19. waheguru
    • 2 years ago
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    the first one \[x^2-7x\]

  20. freckles
    • 2 years ago
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    no @waheguru \[\frac{a}{a} , \text{ assuming of course } a \neq 0\]

  21. freckles
    • 2 years ago
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    =1

  22. estudier
    • 2 years ago
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    Why do I feel like I am talking to myself here?

  23. freckles
    • 2 years ago
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    left out the a/a=1 part

  24. waheguru
    • 2 years ago
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    So the x's cancel out and it becomes 7x?

  25. freckles
    • 2 years ago
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    \[\frac{x(x-7)}{(x-7)}\]

  26. estudier
    • 2 years ago
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    There is no need to multiply initially that is just a waste of time.

  27. freckles
    • 2 years ago
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    What factor does the bottom and top have in common?

  28. waheguru
    • 2 years ago
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    @estudier I know you can cencel out but i wanna try this way

  29. estudier
    • 2 years ago
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    The equation is inconsistent!1111

  30. waheguru
    • 2 years ago
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    x @freckles

  31. freckles
    • 2 years ago
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    The top and bottom both have the factor (x-7) in common

  32. waheguru
    • 2 years ago
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    Yes

  33. estudier
    • 2 years ago
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    I am not cancelling anything.......

  34. estudier
    • 2 years ago
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    x-7/x-7 = -6 is just nonsense

  35. freckles
    • 2 years ago
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    \[\frac{x \not{(x-7)}}{ \not{(x-7)}}\] Imagine that canceler thingy is over the whole factor (x-7) Couldn't do it in latex so we have the first one x So Now try the other two

  36. estudier
    • 2 years ago
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    You two evidently have nothing better to do.....:-)

  37. freckles
    • 2 years ago
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    @estudier I know what you are saying but I just want to convince him

  38. waheguru
    • 2 years ago
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    @estudier Then How do you think we solve this

  39. estudier
    • 2 years ago
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    There is no solution, the equation is not consistent (it is a false equation)

  40. waheguru
    • 2 years ago
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    no its not, there is an asnwer !!!!!!

  41. estudier
    • 2 years ago
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    It is like writing 1= 2

  42. freckles
    • 2 years ago
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    Right but we need to show him that...and convince him... If he doesn't understand your way, then there is no hurt in me showing this other way

  43. freckles
    • 2 years ago
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    @estudier is right there is no solution

  44. waheguru
    • 2 years ago
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    guys ok thanks

  45. estudier
    • 2 years ago
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    He doesn't want to understand it, that is a different thing.

  46. freckles
    • 2 years ago
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    We will get x=7 but that is a contradiction because x cannot be 7

  47. freckles
    • 2 years ago
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    Doing it the way I was trying to show @waheguru

  48. freckles
    • 2 years ago
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    So therefore no solution

  49. estudier
    • 2 years ago
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    When simplifying add or subtract like things first.....

  50. waheguru
    • 2 years ago
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    guys look at this http://www.youtube.com/watch?v=q7_xdLZHN6g the same question appears at about 5 miutes

  51. waheguru
    • 2 years ago
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    this is not impossible noting is

  52. waheguru
    • 2 years ago
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    @estudier @freckles http://www.youtube.com/watch?v=q7_xdLZHN6g at 5 mins

  53. estudier
    • 2 years ago
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    The equation is inconsistent (I don't care what is on youtube)

  54. waheguru
    • 2 years ago
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    Ur right i am so sorry

  55. waheguru
    • 2 years ago
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    I just realized Brother I appoloze

  56. estudier
    • 2 years ago
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    Accepted.

  57. waheguru
    • 2 years ago
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    I was just confued

  58. freckles
    • 2 years ago
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    @waheguru the way the video is doing it was the exact way I was going to show you

  59. freckles
    • 2 years ago
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    Did you see that she got x=7 but then since we have x-7 on bottom then x cannot be 7 so there is no solution

  60. waheguru
    • 2 years ago
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    yea

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