Kay9911
Find (M) when square root of 3/2 = 16.5m



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Kay9911
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help please

Kay9911
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much appreciated

Kay9911
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\[\sqrt{3}\div2 =16.5m\]

Kay9911
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???

sritama
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guess you want the value of m...dw:1342587199895:dw

Kay9911
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that's the problem in the correct format

sritama
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oh yeah , dw:1342587285594:dw

monokerous
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is it \[\sqrt{3 \over 2} or {\sqrt3 \over 2}\]

Kay9911
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it's dw:1342587341741:dw

sritama
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ok,solve for m

Kay9911
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alright to solve for m, should I cross multiply?

sritama
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dw:1342587409613:dw

monokerous
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33m=sqrt3

sritama
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yeah do it..

Kay9911
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ok, that starts like this or something?
dw:1342587533227:dw

sritama
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better not to move sqart 3..you will find the calculation easier

Kay9911
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alright so leave it as the original

sritama
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dw:1342587713630:dw

sritama
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dw:1342587772718:dw

sritama
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dw:1342587804700:dw

Kay9911
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so it will be 33\[\sqrt{3}\]

sritama
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dw:1342587886026:dw

Kay9911
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ooooooooo

sritama
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you got it?

Kay9911
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kind of :D

Kay9911
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it makes better sense now

sritama
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ok,if there is any confusion you can ask.. :)

Kay9911
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so, how did the 11 pop up?
I get the 33 and \[\sqrt{3}\], but 11?

Kay9911
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i couldnt see all of your image reply

sritama
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\[33=11\times3\]

Kay9911
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ok, so that explain the final result

sritama
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\[so,33=11\times \sqrt{3}\times \sqrt{3}\]

sritama
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now your equation is \[\sqrt{3}=11\times \sqrt{3}\times \sqrt{3}\]

Kay9911
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Now I finally get it!

sritama
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now your equation is
3√=11×3√×3√m

sritama
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ok.. :)

sritama
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forgot about m..

Kay9911
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Thank you soooo much for you help!!!

Kay9911
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It means alot!!

sritama
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you are welcome...