Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
i am getting two solutions for this problem. but only one is satisfying the equation. could someone pls explain whats going on...
http://assets.openstudy.com/updates/attachments/50064e0ae4b0624180677e0aemily91021342590484915mathproblem5.jpg
 one year ago
 one year ago
i am getting two solutions for this problem. but only one is satisfying the equation. could someone pls explain whats going on... http://assets.openstudy.com/updates/attachments/50064e0ae4b0624180677e0aemily91021342590484915mathproblem5.jpg
 one year ago
 one year ago

This Question is Closed

ganeshie8Best ResponseYou've already chosen the best response.1
dw:1342591850277:dw
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
x =1 is not satisfying the equation :( not sure why
 one year ago

f1r1e1s1h1Best ResponseYou've already chosen the best response.0
man u have squared it so ofcourse one will not match?
 one year ago

higgsBest ResponseYou've already chosen the best response.1
when you square something, you will always get two solutions, and not all of them will be right. substitute the answers back into the original equation to check. in this case, 1 is not the solution as 1 is not equal to 1
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
im li'l lost.... could u elaborate pls.. ?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
i see we are squaring... and losing sign sensitivity is it
 one year ago

mukushlaBest ResponseYou've already chosen the best response.2
u must consider restrictions in every step note that when u have \( x3=2 \sqrt{x} \) then \( x3 \ge0 \)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
ah that makes sense. thanks mukushla straight to the point. :)
 one year ago

higgsBest ResponseYou've already chosen the best response.1
I suppose this also applies to irrational equations like this? \[\sqrt{x1}+\sqrt{x+4}=\sqrt{3x+10}\] I got \(x = 5\) and \(x = \frac{13}{3} \) \(x = \frac{13}{3} \) is rejected in this case as well because after substituting into the equation, it became undefined.
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
yeah now i understand thanks higgs :D here, from the first equation itself, we can apply the restriction x >=1. and hence rejected solutions < 1
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.