anonymous
  • anonymous
solve without using calculator 5ln(x-2)-2=28 help please, thank you
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
5ln(x-2) = 30
anonymous
  • anonymous
ln(x-2) = 6
anonymous
  • anonymous
ln or log ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Mimi_x3
  • Mimi_x3
\( 5ln(x-2) = 30 \) \(ln(x-2) = 6\) \(log_e(x-2) = 6\) \((x-2) = e^{6}\) Are you able to do it now?
anonymous
  • anonymous
ln
anonymous
  • anonymous
im stuck at the (x-2)=e^6
Mimi_x3
  • Mimi_x3
bring the \(2\) to the RHS
anonymous
  • anonymous
i know the answer is e^6 +2 but i dont know where the =2 comes from
anonymous
  • anonymous
+2
Mimi_x3
  • Mimi_x3
Because when you bring the \(-2\) to the RHS it's a positive
Mimi_x3
  • Mimi_x3
I don't know the correct way to say that lol
anonymous
  • anonymous
alright can you walk me through the part after ln(x-2)=6
Mimi_x3
  • Mimi_x3
Well you know that \(ln\) can also be written as \(log_e\) right?
anonymous
  • anonymous
yea
anonymous
  • anonymous
so you get e^6= (x-2) right
Mimi_x3
  • Mimi_x3
yeah \((x-2) = e^{6}\)
anonymous
  • anonymous
so what do you do next
Mimi_x3
  • Mimi_x3
well i just told you before :)
anonymous
  • anonymous
bring the 2 to the RHS?
anonymous
  • anonymous
ooooohhhhhhhh xD duh x = e^6 + 2
Mimi_x3
  • Mimi_x3
yes; you dont really bring it was called something else which forgot. just simply drag it to RHS. But there is a better name for it lol
anonymous
  • anonymous
i forgot i was solving for x , silly me
anonymous
  • anonymous
i more last question what do you do for e^x-3 = 16
Mimi_x3
  • Mimi_x3
\[ e^x - 3 =16\] What have you tried?
anonymous
  • anonymous
e^x-3 + 4 =20
Mimi_x3
  • Mimi_x3
Um, that is not right..
Mimi_x3
  • Mimi_x3
drag the \(-3) to the rhs
anonymous
  • anonymous
but its an exponent x-3 is the exp. for e
Mimi_x3
  • Mimi_x3
\[ e^x = 16+ 3\]
Mimi_x3
  • Mimi_x3
\[ e^x = 19\]
Mimi_x3
  • Mimi_x3
Take ln both sides \[xlne = ln19\]
anonymous
  • anonymous
the answer is ln(16)+3
Mimi_x3
  • Mimi_x3
Wolfram Alpha agrees with me http://www.wolframalpha.com/input/?i=+e%5Ex-3+%3D+16
anonymous
  • anonymous
my teacger myst be wring though . she gave me that answer
anonymous
  • anonymous
my teacher was wron. she gave me that answer
Mimi_x3
  • Mimi_x3
well there is a low chance that wolfram alpha is wrong
anonymous
  • anonymous
oh, well, it looks like we have a paranthesis confusion here. when writing e^x-3 = 16, it's important that you write the parantheses aroudnthe (x-3), else we can't know that the whole thing is the exponant. So we have this right? \[e ^{x-3} = 16\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.