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youngmath
Group Title
solve without using calculator
5ln(x2)2=28
help please, thank you
 2 years ago
 2 years ago
youngmath Group Title
solve without using calculator 5ln(x2)2=28 help please, thank you
 2 years ago
 2 years ago

This Question is Open

Champs Group TitleBest ResponseYou've already chosen the best response.0
5ln(x2) = 30
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\( 5ln(x2) = 30 \) \(ln(x2) = 6\) \(log_e(x2) = 6\) \((x2) = e^{6}\) Are you able to do it now?
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
im stuck at the (x2)=e^6
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
bring the \(2\) to the RHS
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
i know the answer is e^6 +2 but i dont know where the =2 comes from
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Because when you bring the \(2\) to the RHS it's a positive
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
I don't know the correct way to say that lol
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
alright can you walk me through the part after ln(x2)=6
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Well you know that \(ln\) can also be written as \(log_e\) right?
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
so you get e^6= (x2) right
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
yeah \((x2) = e^{6}\)
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
so what do you do next
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
well i just told you before :)
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
bring the 2 to the RHS?
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
ooooohhhhhhhh xD duh x = e^6 + 2
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
yes; you dont really bring it was called something else which forgot. just simply drag it to RHS. But there is a better name for it lol
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
i forgot i was solving for x , silly me
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
i more last question what do you do for e^x3 = 16
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[ e^x  3 =16\] What have you tried?
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
e^x3 + 4 =20
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Um, that is not right..
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
drag the \(3) to the rhs
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
but its an exponent x3 is the exp. for e
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[ e^x = 16+ 3\]
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
\[ e^x = 19\]
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Take ln both sides \[xlne = ln19\]
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
the answer is ln(16)+3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
Wolfram Alpha agrees with me http://www.wolframalpha.com/input/?i=+e%5Ex3+%3D+16
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
my teacger myst be wring though . she gave me that answer
 2 years ago

youngmath Group TitleBest ResponseYou've already chosen the best response.0
my teacher was wron. she gave me that answer
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.3
well there is a low chance that wolfram alpha is wrong
 2 years ago

m_charron2 Group TitleBest ResponseYou've already chosen the best response.0
oh, well, it looks like we have a paranthesis confusion here. when writing e^x3 = 16, it's important that you write the parantheses aroudnthe (x3), else we can't know that the whole thing is the exponant. So we have this right? \[e ^{x3} = 16\]
 2 years ago
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