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youngmath Group Title

solve without using calculator 5ln(x-2)-2=28 help please, thank you

  • 2 years ago
  • 2 years ago

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  1. Champs Group Title
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    5ln(x-2) = 30

    • 2 years ago
  2. Champs Group Title
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    ln(x-2) = 6

    • 2 years ago
  3. Champs Group Title
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    ln or log ?

    • 2 years ago
  4. Mimi_x3 Group Title
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    \( 5ln(x-2) = 30 \) \(ln(x-2) = 6\) \(log_e(x-2) = 6\) \((x-2) = e^{6}\) Are you able to do it now?

    • 2 years ago
  5. youngmath Group Title
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    ln

    • 2 years ago
  6. youngmath Group Title
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    im stuck at the (x-2)=e^6

    • 2 years ago
  7. Mimi_x3 Group Title
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    bring the \(2\) to the RHS

    • 2 years ago
  8. youngmath Group Title
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    i know the answer is e^6 +2 but i dont know where the =2 comes from

    • 2 years ago
  9. youngmath Group Title
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    +2

    • 2 years ago
  10. Mimi_x3 Group Title
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    Because when you bring the \(-2\) to the RHS it's a positive

    • 2 years ago
  11. Mimi_x3 Group Title
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    I don't know the correct way to say that lol

    • 2 years ago
  12. youngmath Group Title
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    alright can you walk me through the part after ln(x-2)=6

    • 2 years ago
  13. Mimi_x3 Group Title
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    Well you know that \(ln\) can also be written as \(log_e\) right?

    • 2 years ago
  14. youngmath Group Title
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    yea

    • 2 years ago
  15. youngmath Group Title
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    so you get e^6= (x-2) right

    • 2 years ago
  16. Mimi_x3 Group Title
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    yeah \((x-2) = e^{6}\)

    • 2 years ago
  17. youngmath Group Title
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    so what do you do next

    • 2 years ago
  18. Mimi_x3 Group Title
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    well i just told you before :)

    • 2 years ago
  19. youngmath Group Title
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    bring the 2 to the RHS?

    • 2 years ago
  20. youngmath Group Title
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    ooooohhhhhhhh xD duh x = e^6 + 2

    • 2 years ago
  21. Mimi_x3 Group Title
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    yes; you dont really bring it was called something else which forgot. just simply drag it to RHS. But there is a better name for it lol

    • 2 years ago
  22. youngmath Group Title
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    i forgot i was solving for x , silly me

    • 2 years ago
  23. youngmath Group Title
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    i more last question what do you do for e^x-3 = 16

    • 2 years ago
  24. Mimi_x3 Group Title
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    \[ e^x - 3 =16\] What have you tried?

    • 2 years ago
  25. youngmath Group Title
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    e^x-3 + 4 =20

    • 2 years ago
  26. Mimi_x3 Group Title
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    Um, that is not right..

    • 2 years ago
  27. Mimi_x3 Group Title
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    drag the \(-3) to the rhs

    • 2 years ago
  28. youngmath Group Title
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    but its an exponent x-3 is the exp. for e

    • 2 years ago
  29. Mimi_x3 Group Title
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    \[ e^x = 16+ 3\]

    • 2 years ago
  30. Mimi_x3 Group Title
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    \[ e^x = 19\]

    • 2 years ago
  31. Mimi_x3 Group Title
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    Take ln both sides \[xlne = ln19\]

    • 2 years ago
  32. youngmath Group Title
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    the answer is ln(16)+3

    • 2 years ago
  33. Mimi_x3 Group Title
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    Wolfram Alpha agrees with me http://www.wolframalpha.com/input/?i=+e%5Ex-3+%3D+16

    • 2 years ago
  34. youngmath Group Title
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    my teacger myst be wring though . she gave me that answer

    • 2 years ago
  35. youngmath Group Title
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    my teacher was wron. she gave me that answer

    • 2 years ago
  36. Mimi_x3 Group Title
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    well there is a low chance that wolfram alpha is wrong

    • 2 years ago
  37. m_charron2 Group Title
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    oh, well, it looks like we have a paranthesis confusion here. when writing e^x-3 = 16, it's important that you write the parantheses aroudnthe (x-3), else we can't know that the whole thing is the exponant. So we have this right? \[e ^{x-3} = 16\]

    • 2 years ago
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