A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
solve without using calculator
5ln(x2)2=28
help please, thank you
anonymous
 3 years ago
solve without using calculator 5ln(x2)2=28 help please, thank you

This Question is Open

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3\( 5ln(x2) = 30 \) \(ln(x2) = 6\) \(log_e(x2) = 6\) \((x2) = e^{6}\) Are you able to do it now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im stuck at the (x2)=e^6

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3bring the \(2\) to the RHS

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know the answer is e^6 +2 but i dont know where the =2 comes from

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3Because when you bring the \(2\) to the RHS it's a positive

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3I don't know the correct way to say that lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright can you walk me through the part after ln(x2)=6

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3Well you know that \(ln\) can also be written as \(log_e\) right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so you get e^6= (x2) right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what do you do next

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3well i just told you before :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0bring the 2 to the RHS?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ooooohhhhhhhh xD duh x = e^6 + 2

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3yes; you dont really bring it was called something else which forgot. just simply drag it to RHS. But there is a better name for it lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i forgot i was solving for x , silly me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i more last question what do you do for e^x3 = 16

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3\[ e^x  3 =16\] What have you tried?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3Um, that is not right..

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3drag the \(3) to the rhs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but its an exponent x3 is the exp. for e

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3Take ln both sides \[xlne = ln19\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answer is ln(16)+3

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3Wolfram Alpha agrees with me http://www.wolframalpha.com/input/?i=+e%5Ex3+%3D+16

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my teacger myst be wring though . she gave me that answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my teacher was wron. she gave me that answer

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.3well there is a low chance that wolfram alpha is wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, well, it looks like we have a paranthesis confusion here. when writing e^x3 = 16, it's important that you write the parantheses aroudnthe (x3), else we can't know that the whole thing is the exponant. So we have this right? \[e ^{x3} = 16\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.