Select all of the quadrants that the parabola whose equation is y=sqrt(x-4) occupies.
I
II
III
IV
So the basic rules are
x is always positive to the right so: x=ay^2 opens to the right
x is always negative to the left; so x=-ay^2 opens to the left
My problem is: I got rid of the radical by squaring, which gave me y^2 = x-4, then I subtracted x and y^2 from both sides to get -x=-y^2-4. Am I supposed to multiply all numbers by -1 to get rid of the negative numbers or do I just leave it like that?

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@amistre64

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multiply by -1 u will have \( x=y^2+4 \)
can u draw it?

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