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idontgetconicsections
Group Title
Select all of the quadrants that the parabola whose equation is y=sqrt(x4) occupies.
I
II
III
IV
So the basic rules are
x is always positive to the right so: x=ay^2 opens to the right
x is always negative to the left; so x=ay^2 opens to the left
My problem is: I got rid of the radical by squaring, which gave me y^2 = x4, then I subtracted x and y^2 from both sides to get x=y^24. Am I supposed to multiply all numbers by 1 to get rid of the negative numbers or do I just leave it like that?
 2 years ago
 2 years ago
idontgetconicsections Group Title
Select all of the quadrants that the parabola whose equation is y=sqrt(x4) occupies. I II III IV So the basic rules are x is always positive to the right so: x=ay^2 opens to the right x is always negative to the left; so x=ay^2 opens to the left My problem is: I got rid of the radical by squaring, which gave me y^2 = x4, then I subtracted x and y^2 from both sides to get x=y^24. Am I supposed to multiply all numbers by 1 to get rid of the negative numbers or do I just leave it like that?
 2 years ago
 2 years ago

This Question is Closed

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
@amistre64
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
dw:1342621312995:dw
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
multiply by 1 u will have \( x=y^2+4 \) can u draw it?
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
dw:1342621412614:dw
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Or is it only in quadrant 1?
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
u should move it to right
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
dw:1342621507272:dw
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
Well, the answer of a square root is nonnegative.. so definitely can't be 3 or 4
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Like that?
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Thanks
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
No it's not
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
So it's I and IV
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Why?
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Why is it wrong slaaiback?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
I just told you. "Well, the answer of a square root is nonnegative.. so definitely can't be 3 or 4"
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
It's only I then?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
dw:1342621638765:dw
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
Yes. Only 1
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Uhmm... why doesn't it look like a parabola?
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
because I freehanded the graph. Just to illustrate where it goes. You can make it parabolalike yourself
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Haha. Well, I have another question: Score: Select all of the quadrants that the parabola whose equation is y = x²  4 occupies I chose all quadrants... is this correct or is it only 1 and 2 because it's nonnegative?
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
sorry u must consider ristrictions for x ,y from \( y=\sqrt{x4} \) u have y>=0 and x>=4
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
It's all of them. x^2 is nonnegative yes, but x^2  4 is not always nonnegative
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
This is really confusing.. which quadrants does x = y² + 1 occupy? I chose 1 because it's nonnegtaive, but 1 is not negative? So... ?
 2 years ago

idontgetconicsections Group TitleBest ResponseYou've already chosen the best response.1
Oh wait, that's a square root, so it's quadrant 1 and 4??
 2 years ago

myko Group TitleBest ResponseYou've already chosen the best response.0
omg, it's 1 and 4. The quadrants where x is positive
 2 years ago

slaaibak Group TitleBest ResponseYou've already chosen the best response.0
ye 1 and four looks correct to me.
 2 years ago
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