Select all of the quadrants that the parabola whose equation is y=sqrt(x-4) occupies.
I
II
III
IV
So the basic rules are
x is always positive to the right so: x=ay^2 opens to the right
x is always negative to the left; so x=-ay^2 opens to the left
My problem is: I got rid of the radical by squaring, which gave me y^2 = x-4, then I subtracted x and y^2 from both sides to get -x=-y^2-4. Am I supposed to multiply all numbers by -1 to get rid of the negative numbers or do I just leave it like that?

- anonymous

- jamiebookeater

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- anonymous

- anonymous

|dw:1342621312995:dw|

- anonymous

multiply by -1 u will have \( x=y^2+4 \)
can u draw it?

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## More answers

- anonymous

|dw:1342621412614:dw|

- anonymous

Or is it only in quadrant 1?

- anonymous

u should move it to right

- anonymous

|dw:1342621507272:dw|

- slaaibak

Well, the answer of a square root is nonnegative.. so definitely can't be 3 or 4

- anonymous

Like that?

- anonymous

Thanks

- slaaibak

No it's not

- anonymous

So it's I and IV

- anonymous

Why?

- anonymous

Why is it wrong slaaiback?

- slaaibak

I just told you.
"Well, the answer of a square root is nonnegative.. so definitely can't be 3 or 4"

- anonymous

It's only I then?

- slaaibak

|dw:1342621638765:dw|

- slaaibak

Yes. Only 1

- anonymous

Uhmm... why doesn't it look like a parabola?

- slaaibak

because I freehanded the graph. Just to illustrate where it goes. You can make it parabola-like yourself

- anonymous

Haha. Well, I have another question: Score:
Select all of the quadrants that the parabola whose equation is y = x² - 4 occupies
I chose all quadrants... is this correct or is it only 1 and 2 because it's nonnegative?

- anonymous

sorry
u must consider ristrictions for x ,y from \( y=\sqrt{x-4} \) u have y>=0 and x>=4

- slaaibak

It's all of them. x^2 is nonnegative yes, but x^2 - 4 is not always nonnegative

- anonymous

This is really confusing.. which quadrants does x = y² + 1 occupy? I chose 1 because it's nonnegtaive, but 1 is not negative? So... ?

- anonymous

Oh wait, that's a square root, so it's quadrant 1 and 4??

- anonymous

omg, it's 1 and 4. The quadrants where x is positive

- slaaibak

ye 1 and four looks correct to me.

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