kitsune0724
How would solve 3n^44n^2+1=0 by factoring?



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ramya25
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substitute t = n^2

kitsune0724
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My teacher wants us to use either factoring or the quadratic formula on these problems.

ramya25
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Yes. first you have to change it to quadratic then you can factor

kitsune0724
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okay let me see...

ramya25
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kayyy

mukushla
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use this hint
\[\large 3n^44n^2+1=3n^43n^2(n^21)=3n^2(n1)(n1)(n+1)\]

ramya25
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Yes grouping gives quick factors here. check the steps of @mukushla

kitsune0724
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thank y'all.