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kitsune0724 Group Title

How would solve 3n^4-4n^2+1=0 by factoring?

  • 2 years ago
  • 2 years ago

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  1. ramya25 Group Title
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    substitute t = n^2

    • 2 years ago
  2. kitsune0724 Group Title
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    My teacher wants us to use either factoring or the quadratic formula on these problems.

    • 2 years ago
  3. ramya25 Group Title
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    Yes. first you have to change it to quadratic then you can factor

    • 2 years ago
  4. kitsune0724 Group Title
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    okay let me see...

    • 2 years ago
  5. ramya25 Group Title
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    kayyy

    • 2 years ago
  6. mukushla Group Title
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    use this hint \[\large 3n^4-4n^2+1=3n^4-3n^2-(n^2-1)=3n^2(n-1)-(n-1)(n+1)\]

    • 2 years ago
  7. ramya25 Group Title
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    Yes grouping gives quick factors here. check the steps of @mukushla

    • 2 years ago
  8. kitsune0724 Group Title
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    thank y'all.

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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