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kitsune0724
 3 years ago
By factoring how do you solve 3x^2/311x^1/34=0? My teacher doesn't do substitution. please and thank you.
kitsune0724
 3 years ago
By factoring how do you solve 3x^2/311x^1/34=0? My teacher doesn't do substitution. please and thank you.

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cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1(3x^1/3 + 1)(x^1/3  4 ) = 0

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.13x^1/3 + 1 = 0 x^(1/3) = 1/3 x^1/3  4 = 0 x^1/3 = 4

kitsune0724
 3 years ago
Best ResponseYou've already chosen the best response.0(1/3)^3 or (1/3)^3?

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1sorry  i didn't write it corruptly (x^(1/3)^ 3 = x^(1/3 * 3) = x^1 = x or in other words you have the cube root of and you cube it  that gives you x so if you cube both sides of the equations you get the value of x e g (x^(1/3)^ 3 =( 1/3)^3 so x =  1/3^3 = 1/27 thats one of the roots

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1note x^(1/3) is same as cube root x

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1so to find other root you do same thing with x^1/3 = 4

kitsune0724
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you again. But do you divide x^1/3=4? Like 4/1=4.

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1just cube both sides of th equation as we did to the first one (x^(1/3)^3 = x 4^3 = 4*4*4 = 64 x = 64

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1i suggest you review the laws of indices x^a + x^b = x^(a+b) x^a / x^b = x^(ab) (x^a)^b = x^(a*b) = x^ ab

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1also dw:1342632977864:dw

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1please ask if you need any more help

kitsune0724
 3 years ago
Best ResponseYou've already chosen the best response.0Could you please help with another problem?
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