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kitsune0724 Group Title

Would it be easier to factor 12t^2-17t^-1-5=0 or to use the quadratic formula?

  • 2 years ago
  • 2 years ago

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  1. ash2326 Group Title
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    Is this your equation? \[12t^2-17t^{-1}-5=0\]

    • 2 years ago
  2. vamgadu Group Title
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    i dont think you can use the quadratic formula in this case, as we have -ve power in this case.

    • 2 years ago
  3. AnimalAin Group Title
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    \[12t^2-17t^{-1}-5=0\]This one won't factor that well. The problem is probably\[12t^2-17t-5=0\]

    • 2 years ago
  4. AnimalAin Group Title
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    If it is, you can use the ac-method to factor it. Do you know how to do that?

    • 2 years ago
  5. kitsune0724 Group Title
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    Yes, but that's not the method my teacher wants me to use. Thank you.

    • 2 years ago
  6. vamgadu Group Title
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    what is the problem exactly. is it quadratic or not?

    • 2 years ago
  7. kitsune0724 Group Title
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    No. it's not quadratic.

    • 2 years ago
  8. AnimalAin Group Title
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    The quadratic formula only works on quadratic equations.

    • 2 years ago
  9. vamgadu Group Title
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    there must have been a mistake with this problem. anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.

    • 2 years ago
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