anonymous
  • anonymous
Would it be easier to factor 12t^2-17t^-1-5=0 or to use the quadratic formula?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ash2326
  • ash2326
Is this your equation? \[12t^2-17t^{-1}-5=0\]
anonymous
  • anonymous
i dont think you can use the quadratic formula in this case, as we have -ve power in this case.
anonymous
  • anonymous
\[12t^2-17t^{-1}-5=0\]This one won't factor that well. The problem is probably\[12t^2-17t-5=0\]

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anonymous
  • anonymous
If it is, you can use the ac-method to factor it. Do you know how to do that?
anonymous
  • anonymous
Yes, but that's not the method my teacher wants me to use. Thank you.
anonymous
  • anonymous
what is the problem exactly. is it quadratic or not?
anonymous
  • anonymous
No. it's not quadratic.
anonymous
  • anonymous
The quadratic formula only works on quadratic equations.
anonymous
  • anonymous
there must have been a mistake with this problem. anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.

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