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kitsune0724
Would it be easier to factor 12t^2-17t^-1-5=0 or to use the quadratic formula?
Is this your equation? \[12t^2-17t^{-1}-5=0\]
i dont think you can use the quadratic formula in this case, as we have -ve power in this case.
\[12t^2-17t^{-1}-5=0\]This one won't factor that well. The problem is probably\[12t^2-17t-5=0\]
If it is, you can use the ac-method to factor it. Do you know how to do that?
Yes, but that's not the method my teacher wants me to use. Thank you.
what is the problem exactly. is it quadratic or not?
No. it's not quadratic.
The quadratic formula only works on quadratic equations.
there must have been a mistake with this problem. anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.