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Would it be easier to factor 12t^217t^15=0 or to use the quadratic formula?
 one year ago
 one year ago
Would it be easier to factor 12t^217t^15=0 or to use the quadratic formula?
 one year ago
 one year ago

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ash2326Best ResponseYou've already chosen the best response.0
Is this your equation? \[12t^217t^{1}5=0\]
 one year ago

vamgaduBest ResponseYou've already chosen the best response.0
i dont think you can use the quadratic formula in this case, as we have ve power in this case.
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
\[12t^217t^{1}5=0\]This one won't factor that well. The problem is probably\[12t^217t5=0\]
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
If it is, you can use the acmethod to factor it. Do you know how to do that?
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
Yes, but that's not the method my teacher wants me to use. Thank you.
 one year ago

vamgaduBest ResponseYou've already chosen the best response.0
what is the problem exactly. is it quadratic or not?
 one year ago

kitsune0724Best ResponseYou've already chosen the best response.0
No. it's not quadratic.
 one year ago

AnimalAinBest ResponseYou've already chosen the best response.1
The quadratic formula only works on quadratic equations.
 one year ago

vamgaduBest ResponseYou've already chosen the best response.0
there must have been a mistake with this problem. anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.
 one year ago
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