Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

kitsune0724

  • 2 years ago

Would it be easier to factor 12t^2-17t^-1-5=0 or to use the quadratic formula?

  • This Question is Closed
  1. ash2326
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is this your equation? \[12t^2-17t^{-1}-5=0\]

  2. vamgadu
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont think you can use the quadratic formula in this case, as we have -ve power in this case.

  3. AnimalAin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[12t^2-17t^{-1}-5=0\]This one won't factor that well. The problem is probably\[12t^2-17t-5=0\]

  4. AnimalAin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    If it is, you can use the ac-method to factor it. Do you know how to do that?

  5. kitsune0724
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, but that's not the method my teacher wants me to use. Thank you.

  6. vamgadu
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is the problem exactly. is it quadratic or not?

  7. kitsune0724
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No. it's not quadratic.

  8. AnimalAin
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The quadratic formula only works on quadratic equations.

  9. vamgadu
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there must have been a mistake with this problem. anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.