y varies inversely as twice x so $y = \frac{k}{2x}$ when x = 3 then y = 8 $8 = \frac{k}{2(3)} \implies 8 = \frac{k}{6} \implies 48 = k$ find y when x= 2 $y = \frac{k}{2x}$ $y = \frac{48}{2(2)}$ $y = \frac{48}{4}$ $y = 12$ do you get that?